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3 years ago

Meg is packing a shipping conditier.

Mathematics

1 answer:

allochka39001 [22]3 years ago

4 0

Answer:

$Boxes= 198$

Step-by-step explanation:

This question has uncleared details towards the end. However, one can deduce that we need to calculate the amount of box the available space can contain.

We have the following given parameters.

Shipping Container

$Dimension: 2ft\ by\ 3ft\ by\ 33ft$

The box

$Dimension: 1ft\ by\ 1ft\ by\ 1ft$

First, we calculate the volume of the shipping container.

$V_A = 2ft * 3ft * 33ft$

$V_A = 198ft^3$

Next, we calculate the volume of the box.

$V_B = 1ft * 1ft * 1ft$

$V_B = 1ft^3$

The number of box is then calculated as:

$Boxes= \frac{V_A}{V_B}$

$Boxes= \frac{198ft^3}{1ft^3}$

$Boxes= \frac{198}{1}$

$Boxes= 198$

Hence:

198 boxes will occupy the empty space

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Nadya [2.5K]

-30-6r=36

We move all terms to the left:

-30-6r-(36)=0

We add all the numbers together, and all the variables

-6r-66=0

We move all terms containing r to the left, all other terms to the right

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3 years ago

Read 2 more answers

Use the Ratio Test to determine the convergence or divergence of the series. If the Ratio Test is inconclusive, determine the co

jeka57 [31]

Answer:

<h2>A. The series CONVERGES</h2>

Step-by-step explanation:

If $\sum a_n$ is a series, for the series to converge/diverge according to ratio test, the following conditions must be met.

$\lim_{n \to \infty} |\frac{a_n_+_1}{a_n}| = \rho$

If $\rho$ < 1, the series converges absolutely

If $\rho > 1$ , the series diverges

If $\rho = 1$ , the test fails.

Given the series $\sum\left\ {\infty} \atop {1} \right \frac{n^2}{5^n}$

To test for convergence or divergence using ratio test, we will use the condition above.

$a_n = \frac{n^2}{5^n} \\a_n_+_1 = \frac{(n+1)^2}{5^{n+1}}$

$\frac{a_n_+_1}{a_n} = \frac{{\frac{(n+1)^2}{5^{n+1}}}}{\frac{n^2}{5^n} }\\\\ \frac{a_n_+_1}{a_n} = {{\frac{(n+1)^2}{5^{n+1}} * \frac{5^n}{n^2}\$

$\frac{a_n_+_1}{a_n} = {{\frac{(n^2+2n+1)}{5^n*5^1}} * \frac{5^n}{n^2}\\$

aₙ₊₁/aₙ =

$\lim_{n \to \infty} |\frac{ n^2+2n+1}{5n^2}| \\\\Dividing\ through\ by \ n^2\\\\\lim_{n \to \infty} |\frac{ n^2/n^2+2n/n^2+1/n^2}{5n^2/n^2}|\\\\\lim_{n \to \infty} |\frac{1+2/n+1/n^2}{5}|\\\\$

note that any constant dividing infinity is equal to zero

$|\frac{1+2/\infty+1/\infty^2}{5}|\\\\$

$\frac{1+0+0}{5}\\ = 1/5$

$\rho = 1/5$

Since The limit of the sequence given is less than 1, hence the series converges.

5 0

3 years ago

There are 20 pieces of fruit in a bowl and 3 of them are oranges. What percentage of the pieces of fruit in the bowl are oranges

galben [10]

15 percent of the fruit in the fruit bowl are oranges

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3 years ago

Write an equation reprezeting x axis

Rudiy27

Answer:

y=0

Step-by-step explanation:

All y-values along the x-axis are equal to 0.

3 0

3 years ago

1 point

weeeeeb [17]

Answer:

The answer is 0.71 per ounce.

Step-by-step explanation:

You can use proportions to solve this.

$\frac{89.95 dollars}{64lb} = \frac{1 dollar}{x} \\64 * 1 = 64\\89.95 * x = 89.95x\\\\\frac{64}{89.95} = \frac{89.95x}{89.95}\\\\0.7115063924 = x\\Which when rounded to the nearest hundredths is:\\0.71$

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3 years ago