Answer:
7 m/s²
Explanation:
From the question given above, the following data were:
Force applied (Fₐ) = 15 N
Mass (m) of block = 1.5 Kg
Acceleration due to gravity (g) = 10 m/s²
Coefficient of friction (μ) = 0.3
Acceleration (a) of block =?
Next, we shall determine the frictional force. This can be obtained as follow:
Mass (m) of block = 1.5 Kg
Acceleration due to gravity (g) = 10 m/s²
Coefficient of friction (μ) = 0.3
Normal reaction (R) = mg = 1.5 × 10 = 15 N
Frictional force (Fբ) =?
Fբ = μR
Fբ = 0.3 × 15
Fբ = 4.5 N
Next, we shall determine the net force acting on the block. This can be obtained as follow:
Force applied (Fₐ) = 15 N
Frictional force (Fբ) = 4.5 N
Net force (Fₙ) =.?
Fₙ = Fₐ – Fբ
Fₙ = 15 – 4.5
Fₙ = 10.5 N
Finally, we shall determine the acceleration produced in the block. This can be obtained as follow:
Mass (m) of block = 1.5 Kg
Net force (Fₙ) = 10.5 N
Acceleration (a) of block =?
Fₙ = ma
10.5 = 1.5 × a
Divide both side by a
a = 10.5 / 1.5
a = 7 m/s²
Therefore, the acceleration produced in the block is 7 m/s²
