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3 years ago

As a rubber band and moves forward, which of the following is true

Physics

1 answer:

Yuki888 [10]3 years ago

7 0

Answer:

It can go back to it's original shape

Explanation:

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Coach Reese ran 3 km in 30 minutes. What is his average rate of speed in<br> km/hr?

natka813 [3]

Answer:

6 km in 60 minutes or 1 hour

Explanation:

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4 years ago

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Naddik [55]

Answer:

23.5

Explanation:

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3 years ago

Which statement is true about vectors?

lora16 [44]

Vectors need direction and magnitude to exist, otherwise, it becomes scalars that do not require direction to be expressed.

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5 0

3 years ago

Read 2 more answers

Which of the following (with specific heat capacity provided) would show the smallest temperature change upon gaining 200.0 J of

sergij07 [2.7K]

Answer:

A) 50.0 g Al

Explanation:

We can calculate the temperature change of each substance by using the equation:

$\Delta T=\frac{Q}{mC_s}$

where

Q = 200.0 J is the heat provided to the substance

m is the mass of the substance

$C_s$ is the specific heat of the substance

Let's apply the formula for each substance:

A) m = 50.0 g, Cs = 0.903 J/g°C

$\Delta T=\frac{200}{(50)(0.903)}=4.4^{\circ}C$

B) m = 50.0 g, Cs = 0.385 J/g°C

$\Delta T=\frac{200}{(50)(0.385)}=10.4^{\circ}C$

C) m = 25.0 g, Cs = 0.79 J/g°C

$\Delta T=\frac{200}{(25)(0.79)}=10.1^{\circ}C$

D) m = 25.0 g, Cs = 0.128 J/g°C

$\Delta T=\frac{200}{(25)(0.128)}=62.5^{\circ}C$

E) m = 25.0 g, Cs = 0.235 J/g°C

$\Delta T=\frac{200}{(25)(0.235)}=34.0^{\circ}C$

As we can see, substance A) (Aluminium) is the one that undergoes the smallest temperature change.

7 0

3 years ago

A pitot tube system measures the static pressure in 50 cm diameter duct containing air (\rho\:=rho =1.1 kg/m3) as 97 kPa and the

erastova [34]

Answer:

The velocity in duct is 73.854 m/s.

Explanation:

Given that Pitot tube measuring velocity v in 50 cm diameter duct contain air of density 1.1 $\frac{kg}{m^{3} }$ .

Also, P1 = Pressure in duct is 97kpa and P2 = Pressure at impact or stagnation point is 100kpa.

Using Bernoulli equation,

$P+\frac{1}{2}\rho v^{2} +\rho gh=0$

When air is flowing through duct,

$97,000+\frac{1}{2}\rho v^{2} +\rho gh1=0$

When air is at stagnation point.

$1,00,000+0+\rho gh1=0$

Comparing both the equation,

$97,000+\frac{1}{2}\rho v^{2} +\rho gh1=1,00,000+\rho gh1$

$\frac{1}{2}\rho v^{2}=3000$

$0.55v^{2}=3000$

$v^{2}=5454.54$

v=73.854 m/s.

Therefore, The velocity in duct is 73.854 m/s.

4 0

3 years ago