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3 years ago

6

What is f(x)•g(x)? f(x) = 2–2x+1 g(x) = 2x+1

1 answer:

Arada [10]3 years ago

5 0

Answer:

fx

Step-by-step explanation:

just did it

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2 years ago

Solve the given equation for x.<br><br> 2x-B = 10

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3 years ago

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This legend about Admiral Nelson, like other

il63 [147K]

Correct option is E, like legends about other naval heroes, is

It does this by contrasting "this legend" with "legends about other naval heroes," so avoiding the mistake of the original. There is an unreasonable comparison in option (A). "This legend" is contrasted with "other naval heroes."

There is an agreement mistake in option (B). For the single subject "this legend," the plural verb "are" is used. There is an unreasonable comparison in option (C). "This legend" is contrasted with "other naval heroes." Choice (D) has an agreement mistake.

For the single subject "this legend," the plural verb "are" is used. Option E can be used to rewrite the sentence's highlighted portion. By contrasting "this legend" with "legends about other naval heroes," the inaccuracy is fixed. As a result, choice E is the right answer.

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1 year ago

A certain kind of sheet metal has, on average, 3 defects per 18 square feet. Assuming a Poisson distribution, find the probabili

Fofino [41]

Answer:

75.8% probability that a 31 square foot metal sheet has at least 4 defects.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given time interval.

In this problem, we have that:

3 defects per 18 square feet.

So for 31 square feet, we have to solve a rule of three

3 defects - 18 square feet

x defects - 31 square feet

$18x = 3*31$

$x = \frac{31*3}{18}$

$x = 5.17$

So $\mu = 5.17$

Assuming a Poisson distribution, find the probability that a 31 square foot metal sheet has at least 4 defects.

Either it has three or less defects, or it has at least 4 defects. The sum of the probabilities of these events is decimal 1.

So

$P(X \leq 3) + P(X \geq 4) = 1$

We want $P(X \geq 4)$

So

$P(X \geq 4) = 1 - P(X \leq 3)$

In which

$P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)$

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-5.17}*(5.17)^{0}}{(0)!} = 0.0057$

$P(X = 1) = \frac{e^{-5.17}*(5.17)^{1}}{(1)!} = 0.0294$

$P(X = 2) = \frac{e^{-5.17}*(5.17)^{2}}{(2)!} = 0.0760$

$P(X = 3) = \frac{e^{-5.17}*(5.17)^{3}}{(3)!} = 0.1309$

So

$P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0.0057 + 0.0294 + 0.0760 + 0.1309 = 0.242$

Finally

$P(X \geq 4) = 1 - P(X \leq 3) = 1 - 0.242 = 0.758$

75.8% probability that a 31 square foot metal sheet has at least 4 defects.

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3 years ago

I'm stuck and want to make sure I'm doing it right.

murzikaleks [220]

The answers is 3¾ hours

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3 years ago

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