1) -13 = -4a - 2b + c
-13 = -2(2a + b) + c
2) 3 = 4a + 2b +c
3 = 2(2a + b) + c
3) 5 = 16a + 4b + c
5 = 4(4a + b) + c
[ Final Answers are in bold ]
Hope this helps!
There are several ways this can be accomplished. Students could survey every 20 students until they've asked 100 students, or they could ask 1 or 2 people at each cafeteria table during each lunch, just for examples.
Answer: √117
Step-by-step explanation:
Since no diagram present, am assuming hypotenuse AB and right angle C. Let side opp angle B be b, and side opposite angle A be a. Altitude CD is x.
a^2 + b^2 = 22^2 (Pythagorean)
Using Pythag on two smaller triangles,
x^2 + 13^2 = a^2
x^2 + 9^2 = b^2
Substituting in first equation,
x^2 + 13^2 + x^2 + 9^2 = 22^2
x^2 = 117, so x = √117
For this case we must find the value of the variable "x" of the following equation:
So, we follow the steps:
Subtracting 3 from both sides of the equation we have:
Different signs are subtracted and the sign of the major is placed:
Thus, the value of x is 9.
Answer:
