Answer:
The answer is 4.28 moles
Explanation:
This is super easy okay, you won't forget this!
Basically mole ratios, we're just looking at the coefficients in front of the compounds, multiplying them, and dividing them as we see fit.
In this example, you can see how you need 2 moles of lithium bromide (LiBr) for the reaction, and 2 moles of lithium chloride (LiCl) will be produced.
Basically, the <u>molar ratio</u> is when you divide numbers and see how much of this do I have for that (if that makes sense).
So if you were to divide the 2 moles of LiBr / 2 moles of LiCl = 1. So we know that the mole ratio for LiBr to LiCl is 1:1 or 2:2, either or, it's the same thing.
SO THE BIG IDEA, if we have 4.28 moles of lithium bromide reacting, we should also have 4.28 moles of lithium chloride produced, BECAUSE the <u>mole ratio</u> is 1:1.
I hope this makes sense please tell me if it doesn't, I will try my best to explain a little more.
Has markings along the cylinder/beaker that indicate the volume of liquid inside them. .
Depends how many sig figs you are rounding to so I won't round to tenth or hundredth but the answer is 2.037 * 10^7
Answer: 0.028 grams
Explanation:
Depression in freezing point :
Formula used for lowering in freezing point is,
![\Delta T_f=k_f\times m](https://tex.z-dn.net/?f=%5CDelta%20T_f%3Dk_f%5Ctimes%20m)
or,
![\Delta T_f=k_f\times \frac{\text{ Mass of solute in g}\times 1000}{\text {Molar mass of solute}\times \text{ Mass of solvent in g}}](https://tex.z-dn.net/?f=%5CDelta%20T_f%3Dk_f%5Ctimes%20%5Cfrac%7B%5Ctext%7B%20Mass%20of%20solute%20in%20g%7D%5Ctimes%201000%7D%7B%5Ctext%20%7BMolar%20mass%20of%20solute%7D%5Ctimes%20%5Ctext%7B%20Mass%20of%20solvent%20in%20g%7D%7D)
where,
= change in freezing point
= freezing point constant (for benzene} =![5.12^0Ckg/mol](https://tex.z-dn.net/?f=5.12%5E0Ckg%2Fmol)
m = molality
Putting in the values we get:
![0.400^0C=5.12\times \frac{\text{ Mass of solute in g}\times 1000}{354.5\times 209.0}](https://tex.z-dn.net/?f=0.400%5E0C%3D5.12%5Ctimes%20%5Cfrac%7B%5Ctext%7B%20Mass%20of%20solute%20in%20g%7D%5Ctimes%201000%7D%7B354.5%5Ctimes%20209.0%7D)
![{\text{ Mass of solute in g}}=0.028g](https://tex.z-dn.net/?f=%7B%5Ctext%7B%20Mass%20of%20solute%20in%20g%7D%7D%3D0.028g)
0.028 grams of DDT (solute) must be dissolved in 209.0 grams of benzene to reduce the freezing point by 0.400°C.
Answer:
Acceleration = (v Final −v Initial)/(t Final −t Initial). Where v stands for velocity and t stands for time. In algebraic notation, the formula can be expressed as: a=Δv/Δt; Acceleration can be defined as the rate of change of velocity with respect to time.