The <u>correct net ionic equation</u> for the chemical equation involving the reactants Ba(OH)2(aq) and H2SO4(aq) is Ba²⁺ (aq) + 2OH⁻ (aq) + 2H⁺(aq) + SO4²⁻ (aq) --> BaSO₄(s) + H₂O(l)
<h3>Further Explanation
</h3>
The chemical reaction between Ba(OH)2(aq) and H2SO4(aq) will be given by;
Ba(OH)₂(aq) + H₂SO4(aq) --> BaSO₄(aq) + 2H₂O(l)
<h3>Net ionic equations </h3>
- Net ionic equations that do not include all ions that are present in the reactants and products.
- The equations only includes the ions that are involved in the reaction.
- The ions that are not involved in a chemical reaction are called spectator ions and are cancelled out while writing ionic equations.
- Reaction between Ba(OH)2(aq) and H2SO4(aq is an example of a neutralization reaction or a double displacement reaction.
- During the reaction Barium ion bonds with sulfate ions and forms barium sulfate which is a solid, while hydrogen ion bonds with hydroxide ion to form water which is a liquid
That is:
Ba(OH)₂(aq) + H₂SO4(aq) --> BaSO₄(s) + 2H₂O(l)
- Barium ion changes from aqueous to solid state barium sulfate there it is an ion involved in the reaction.
- Additionally, all the other ions are also involved in the reaction since they have changed their initial state. The chemical reaction has no spectator ions.
Therefore; the ionic equation required will be;
Ba²⁺ (aq) + 2OH⁻ (aq) + 2H⁺(aq) + SO4²⁻ (aq) --> BaSO₄(s) + H₂O(l)
Keywords: Net ionic equations
<h3>Learn more about; </h3>
Level: High school
Subject: Chemistry
Topic: Chemical equation
Sub-topic: Net ionic equations
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Answer
is: volume is 20 mL.<span>
c</span>₁(CH₃COOH) = 2,5 M.<span>
c</span>₂(CH₃COOH) = 0,5 M.<span>
V</span>₂(CH₃COOH) = 100 mL.<span>
V</span>₁(CH₃COOH) = ?<span>
c</span>₁(CH₃COOH) · V₁(CH₃COOH)
= c₂(CH₃COOH) · V₂(CH₃COOH).<span>
2,5 M · V</span>₁(CH₃COOH)
= 0,5 M · 100 mL.<span>
V</span>₁(CH₃COOH) = 0,5 M · 100 mL ÷ 2,5 M.<span>
V</span>₁(CH₃COOH) = 20 mL ÷ 1000 mL/L =0,02 L.
Answer:
Following are the <span>conjugate acid-base pairs;
1) NH</span>₃ , NH₄⁺
2) CH₃CO₂⁻ , CH₃COOH
Explanation:
According to Brønsted–Lowry acid–base theory an acid is any specie which can donate H⁺. When an acid donates proton it is converted into conjugate base.
Example:
CH₃COOH + BASE → CH₃COO⁻ + Base-H
In above reaction Acetic Acid (CH₃COOH) is acid, and after loosing proton it is converted into conjugate base i.e. Acetate (CH₃COO⁻).
And according to Brønsted–Lowry acid–base theory base is any specie which can accept H⁺. When base accepts proton it is converted into conjugate acid.
Example:
NH₃ + A-H → NH₄⁺ + A⁻
In above reaction Ammonia (NH₃) is a base, and after accepting proton it is converted into conjugate acid i.e. Ammonium (NH₄⁺)