To solve this question, we first need to know the mass of one mole of mercury. This can be done by checking the periodic table.
From the periodic table, we can see that:
molar mass of mercury = 200.59 grams/mole.
From the measurements, the chemist found that the participated amount of mercury is 0.02 moles.
We can simply determine the mass of 0.02 moles by doing cross multiplication as follows:
mass of 0.02 moles = (0.02 x 200.59) / 1 = 4.0118 grams
Rounding the answer to 2 significant digits, we get:
mass of 0.02 moles = 4.01 grams
Answer:
itz elementary school in new Jersey city and I was in school for a little while I had a phone and a couple days later and I'm going next week and I'm gonna go back and watch Netflix and get some headphones and a lot more like a child and a couple more like this
The lowest time = salt water . ocean water freezes at lower temperatures than fresh waters.
The rate of reaction is always expressed in concentration per time like mol/L·s. The equation is:
r [mol/L·s] = kCⁿ, where n is the order of reaction. Since k is 1300/s, that means that Cⁿ = C such that (1/s)*(mol/L) = mol/L·s. Thus, n=1. For a first order reaction, the formula would be:
ln(A/A₀) = -kt
where
A is the amount of material after time t
A₀ is the amount of material at t=0
The half life is when A/A₀ = 1/2÷1 = 1/2. Thus, the half-life t is:
ln(1/2) = (-1300t)
t = 5.33×10⁻⁴ seconds
