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Umnica [9.8K]
3 years ago
10

Given the figure below, find the measure of​

Mathematics
1 answer:
Scilla [17]3 years ago
6 0

Answer:

x = 23.125°

Step-by-step explanation:

∠ACF = ∠GCB (vertically opposite angles)

3x + 5x - 5 = 180° (angles on a straight line are supplementary)

8x = 185°

x = 23.125°

This is a question on angles. If you wish to venture further into it/understand this topic better, you may want to follow my Instagram account (learntionary), where I post some of my own notes on certain topics and also some tips that may be useful to you :)

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Help im doing a math test
mixer [17]

Answer:

Same doing a quiz too bro

Step-by-step explanation:

5 0
3 years ago
Leah invested $950 in an account paying an interest rate of 1.5% compounded continuously. Assuming no deposits or withdrawals ar
Contact [7]

\bf ~~~~~~ \textit{Continuously Compounding Interest Earned Amount} \\\\ A=Pe^{rt}\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill & \$950\\ r=rate\to 1.5\%\to \frac{1.5}{100}\dotfill &0.015\\ t=years\dotfill &6 \end{cases} \\\\\\ A=950e^{0.015\cdot 6}\implies A=950e^{0.09}\implies A\approx 1039.5\implies \stackrel{\textit{rounded up}}{A=1040}

6 0
4 years ago
Suppose I ask you to pick any four cards at random from a deck of 52, without replacement, and bet you one dollar that at least
Tatiana [17]

Answer:

a) No, because you have only 33.8% of chances of winning the bet.

b) No, because you have only 44.7% of chances of winning the bet.

Step-by-step explanation:

a) Of the total amount of cards (n=52 cards) there are 12 face cards (3 face cards: Jack, Queen, or King for everyone of the 4 suits: clubs, diamonds, hearts and spades).

The probabiility of losing this bet is the sum of:

- The probability of having a face card in the first turn

- The probability of having a face card in the second turn, having a non-face card in the first turn.

- The probability of having a face card in the third turn, having a non-face card in the previous turns.

- The probability of having a face card in the fourth turn, having a non-face card in the previous turns.

<u><em>1) The probability of having a face card in the first turn</em></u>

In this case, the chances are 12 in 52:

P_1=P(face\, card)=12/52=0.231

<u><em>2) The probability of having a face card in the second turn, having a non-face card in the first turn.</em></u>

In this case, first we have to get a non-face card (there are 40 in the dech of 52), and then, with the rest of the cards (there are 51 left now), getting a face card:

P_2=P(non\,face\,card)*P(face\,card)=(40/52)*(12/51)=0.769*0.235=0.181

<u><em>3) The probability of having a face card in the third turn, having a non-face card in the first and second turn.</em></u>

In this case, first we have to get two consecutive non-face card, and then, with the rest of the cards, getting a face card:

P_3=(40/52)*(39/51)*(12/50)\\\\P_3=0.769*0.765*0.240=0.141

<u><em>4) The probability of having a face card in the fourth turn, having a non-face card in the previous turns.</em></u>

In this case, first we have to get three consecutive non-face card, and then, with the rest of the cards, getting a face card:

P_4=(40/52)*(39/51)*(38/50)*(12/49)\\\\P_4=0.769*0.765*0.76*0.245=0.109

With these four probabilities we can calculate the probability of losing this bet:

P=P_1+P_2+P_3+P_4=0.231+0.181+0.141+0.109=0.662

The probability of losing is 66.2%, which is the same as saying you have (1-0.662)=0.338 or 33.8% of winning chances. Losing is more probable than winning, so you should not take the bet.

b) If the bet involves 3 cards, the only difference with a) is that there is no probability of getting the face card in the fourth turn.

We can calculate the probability of losing as the sum of the first probabilities already calculated:

P=P_1+P_2+P_3=0.231+0.181+0.141=0.553

There is 55.3% of losing (or 44.7% of winning), so it is still not convenient to bet.

5 0
4 years ago
Can someone explain box plots
slamgirl [31]

The correct answer is C because the lowest number is 4 ( out of all the numbers ), which is the dot to the above the number 4 and the largest number is 14, that is also marked by a dot above the number 18. The medians are ( the middle number ) 8 and 10, so you are going to add these to numbers together, 8 + 10 = 18, and then you have to divide it by 2, 18 ÷ 2 = 9, which means the median is 9, which is the middle line. For the 1st quartile, you have to add both the 7's and divide by 2, 7+7=14 ÷ 2 = 7, so then the 1st quartile is 7, the line closest to the 4, repeat this for the 3rd quartile, 11 + 13 = 24 ÷ 2 = 12, 3rd quartile = 12, the line closest to the number 14.

8 0
3 years ago
3x-6y=15<br> -3x-9y=-30<br><br> Please help!! Its due in 30 minutes!!
olchik [2.2K]

Step-by-step explanation:

Refer to the attachment.

I hope it helps:)

3 0
3 years ago
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