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3 years ago

What size volumetric flask would you use to create a 1.00M solution using 166.00 g of KI?

Chemistry

1 answer:

mr Goodwill [35]3 years ago

3 0

Answer:

A 1 liter volumetric flask should be used.

Explanation:

First we convert 166.00 g of KI into moles, using its molar mass:

Molar mass of KI = Molar mass of K + Molar mass of I = 166 g/mol

166.00 g ÷ 166 g/mol = 1 mol KI

Then we calculate the required volume, using the definition of molarity:

Molarity = moles / liters

Liters = moles / molarity

1 mol / 1.00 M = 1 L

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Calculate the number of hydrogen atoms in 33.0 g CH4

Elena-2011 [213]

Answer:

The number of hydrogen atoms is 4.96x10²⁴.

Explanation:

The number of atoms can be found with the following equation:

$n = N*\eta_{H}$

Where:

N: is the Avogadro's number = 6.022x10²³ atoms/mol

η: is the number of moles of hydrogen

n: is the number of hydrogen atoms

First, we need to find the number of hydrogen moles. The number of moles of CH₄ is:

$\eta_{CH_{4}} = \frac{m}{M}$

Where:

m: is the mass of methane = 33 g

M: is the molar mass of methane = 16.04 g/mol

$\eta_{CH_{4}} = \frac{33 g}{16.04 g/mol} = 2.06 mol$

Now, since we have 4 hydrogen atoms in 1 mol of methane, the number of moles of hydrogen is:

$\eta_{H} = 2.06\: mol\: CH_{4}*4 \frac{mol\: H}{mol \: CH_{4}} = 8.24 mol$

Hence, the number of hydrogen atoms is:

$n = N*\eta_{H} = 6.022 \cdot 10^{23} \: atoms/mol*8.24 mol = 4.96 \cdot 10^{24} atoms$

Therefore, the number of hydrogen atoms is 4.96x10²⁴.

I hope it helps you!

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