37.8 g CH2Br2 X (1 mol CH2Br2 / 173.83 g) = 4.60X10^-3 mol CH2Br2
<span>4.60X10^-3 mol CH2Br2 X (2 mol Br / 1 mol CH2Br2) X 6.02X10^23 atoms/mol = 5.54X10^21 bromine atoms.
I think this is the answer.</span>
Answer:
the chemical equation is balanced ❤
Answer:
43.5 moles of HNO₃.
Explanation:
The balanced equation for the reaction is given below:
S + 6HNO₃ —> H₂SO₄ + 6NO₂ + 2H₂O
From the balanced equation above,
6 moles of HNO₃ reacted to produce 2 moles of H₂O.
Finally, we shall determine the number of mole of HNO₃ required to produce 14.5 moles of H₂O.
This can be obtained as illustrated below:
From the balanced equation above,
6 moles of HNO₃ reacted to produce 2 moles of H₂O.
Therefore, Xmol of HNO₃ will react to produce 14.5 moles of H₂O i.e
Xmol of HNO₃ = (6 × 14.5)/2
Xmol of HNO₃ = 43.5 moles
Therefore, 43.5 moles of HNO₃ is required to produce 14.5 moles of H₂O.
The answer is four because if you multiply seven times four you will get twenty eight
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