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denis-greek [22]
3 years ago
11

For the chemical reaction 2HBr(aq)+Ba(OH)2(aq)⟶2H2O(l)+BaBr2(aq) write the net ionic equation, including the phases.

Chemistry
1 answer:
Crazy boy [7]3 years ago
8 0

Answer:

2H⁺(aq) + 2OH⁻(aq)  --> 2H2O(l)

Explanation:

2HBr(aq)+Ba(OH)2(aq)⟶2H2O(l)+BaBr2(aq)

We break the compounds into ions. Only compounds in the aqueous form can be turned into ions.

The ionic equation is given as;

2H⁺(aq)  +  2Br⁻(aq)  + Ba²⁺(aq) + 2OH⁻(aq)   --> 2H2O(l)  +  Ba²⁺(aq)  + 2Br⁻(aq)

Upon eliminating the spectator ions; The net equation is given as;

2H⁺(aq) + 2OH⁻(aq)  --> 2H2O(l)

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If 30 grams of KCl is dissolved at 10°C, 14 g of KCl should be added to make a saturated solution at 60 °C.

<h3>What is a saturated solution?</h3>

A saturated solution is a solution in which there is so much solute that if there was any more, it would not dissolve. Its concentration is the same as the solubility at that temperature.

  • Step 1. Calculate the mass of water.

At 10 °C, the solubility is 31.2 g KCl/100 g H₂O.

30 g KCl × 100 g H₂O/31.2 g KCl = 96 g H₂O

  • Step 2. Calculate the mass of KCl required to prepare a saturated solution at 60 °C.

At 60 °C, the solubility is 45.8 g KCl/100 g H₂O.

96 g H₂O × 45.8 g KCl/100 g H₂O = 44 g KCl

  • Step 3. Calculate the mass of KCl that must be added.

44 g - 30 g = 14 g

If 30 grams of KCl is dissolved at 10°C, 14 g of KCl should be added to make a saturated solution at 60 °C.

Learn more about saturated solutions here: brainly.com/question/24564260

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