In order to solve this problem, we transform the statements into
algebraic expressions. First, we assign the variables.
Let:
x = Gina’s number
y = Sara’s number
For the first equation, we show that Gina’s number is greater
than Sara’s number by 2. For the second equation, we show that the sum of both
numbers is 68.
<span>(1)
</span>x – y = 2
<span>(2)
</span>x + y = 68
<span>We
add the two expressions, which result in the expression: 2x = 70. Then we
divide 70 by 2 to get the value of x. We then have x = 35. Using the second
equation, we solve for y = 68-35. This gives y = 33. To summarize, Gina’s
number is 35 while Sara’s number is 33.</span>
Answer:
Step-by-step explanation:
Answer: " m = zC / (C − z) " .
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Explanation:
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Given: 1/C + 1/m = 1/z ; Solve for "m".
Subtract "1/C" from each side of the equation:
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1/C + 1/m − 1/C = 1/z − 1/C ;
to get: 1/m = 1/z − 1/C ;
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Now, multiply the ENTIRE EQUATION (both sides); by "(mzC"); to get ride of the fractions:
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mzC {1/m = 1/z − 1/C} ;
to get: zC = mC − mz ;
Factor out an "m" on the "right-hand side" of the equation:
zC = m(C − z) ; Divide EACH side of the equation by "(C − z)" ; to isolate "m" on one side of the equation;
zC / (C − z) = m(C − z) / m ; to get: 24/8 = 3 24
zC/ (C − z) = m ; ↔ m = zC/ (C − z) .
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Answer:Irrational
Step-by-step explanation: There is not a number you can square to get 23. The answer would be a repeating number, being irrational.
Let the attendees in opposition be x. This means that the attendees in favour are x+6.
That means x+x+6=42, which is 2x+6=42, so 2x=36 and x=18. Therefore, there are 18 attendees who opposed it.
