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lukranit [14]
3 years ago
6

All mutations _____.

Chemistry
1 answer:
yanalaym [24]3 years ago
4 0
Could u provide more like on what to answer this so confusing
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When the equation __H2O2 --> __H2O + __O2 Is completely balanced, the sum of all the coefficients will be A) 5 B) 8 C) 3 D) 4
kkurt [141]

Answer:

A)5

Explanation:

2H2O2 --> 2H2O + 1O2

2+2+1=5

sum=5

8 0
3 years ago
What is the percent composition of phosphoric acid (H3PO4)?
aleksklad [387]

Answer:

H3PO4 Mol mass..

= (3 x H1 = 3) + (1 x P31 = 31) + (4 x O16 = 64). = 98g/mol.

a)..Hydrogen: = 3 / 98 = 0.0306 x 100% = 3.06%.

b)..Phosphorus = 31/98 = 0.3162 x 100% = 31.63%.

c)..Oxygen = 64/98 = 0.6531 x 100% = 65.31%.

(Total = 100% H3PO4).

Explanation:

Find the molar mass of all the elements in the compound in grams per mole.

Find the molecular mass of the entire compound.

Divide the component's molar mass by the entire molecular mass.

You will now have a number between 0 and 1. Multiply it by 100% to get percent composition.

8 0
3 years ago
Which sequence represents heat being removed from matter?
Art [367]

c. gas - liquid - solid


6 0
3 years ago
An initial mixture of nitrogen gas and hydrogen gas is reacted in a rigid container at a certain temperature as follows:
krok68 [10]

Answer:

The concentration of nitrogen gas and hydrogen gas that reacted initially are 10.0 M and 11.0 M respectively.

<em>Note: The question is incomplete. The complete question is as follows:</em>

<em>An initial mixture of nitrogen gas and hydrogen gas is reacted in a rigid container at a certain temperature as follows:</em>

<em>3H2(g)+N2(g)⇌2NH3(g)</em>

<em>At equilibrium, the concentrations are</em>

<em>[H2] = 5.0 M, [N2] = 8.0 M, and [NH3] = 4.0 M.</em>

<em>What were the concentrations of nitrogen gas and hydrogen gas that were reacted initially?</em>

Explanation:

Given the following data:

Concentration of H2 at equilibrium = 5.0 M

Concentration of N2 at equilibrium = 8.0 M

Concentration of NH3 at equilibrium = 4.0 M

The given equilibrium reaction is,

Initial                    a             b            c

Change                -3x          -x         +2x

Equilibrium         (a-3x)       (b-x)     +2x

The value of x is calculated from the equilibrium of NH3

Concentration of NH3 at equilibrium = 4.0 M  = 2x

x = 2.0 M

Substituting the value of x above

Initial Concentration of H2:

a - 3 × 2.0 M = 5.0 M

a = 6.0 M + 5 = 11.0 M

Initial Concentration of N2:

b - 2.0 M = 8 M

b = 8.0 M + 2.0 M

b = 10.0 M

Therefore, the concentration of nitrogen gas and hydrogen gas that reacted initially are 10.0 M and 11.0 M respectively.

3 0
3 years ago
Can someone help please?
attashe74 [19]
<h3>Take the weighted average of the individual isotopes.</h3><h3 /><h3>Explanation:</h3><h3>63</h3><h3>C</h3><h3>u</h3><h3> has </h3><h3>69.2</h3><h3>%</h3><h3> abundance.</h3><h3 /><h3>65</h3><h3>C</h3><h3>u</h3><h3> has </h3><h3>30.8</h3><h3>%</h3><h3> abundance.</h3><h3 /><h3>So, the weighted average is </h3><h3>62.93</h3><h3>×</h3><h3>69.2</h3><h3>%</h3><h3> </h3><h3>+</h3><h3> </h3><h3>64.93</h3><h3>×</h3><h3>30.8</h3><h3>%</h3><h3> </h3><h3>=</h3><h3> </h3><h3>63.55</h3><h3> </h3><h3>amu</h3><h3> .</h3><h3 /><h3>If we look at the Periodic Table, copper metal (a mixture of isotopes but </h3><h3>63</h3><h3>C</h3><h3>u</h3><h3> and </h3><h3>65</h3><h3>C</h3><h3>u</h3><h3> predominate) has an approximate atomic mass of </h3><h3>63.55</h3><h3> </h3><h3>g</h3><h3>⋅</h3><h3>m</h3><h3>o</h3><h3>l</h3><h3>−</h3><h3>1</h3><h3> , so we know we are right.</h3>

4 0
3 years ago
Read 2 more answers
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