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3 years ago

How many lone pairs of electrons are on the central carbon atom in a Lewis Structure of CHI3?

Chemistry

1 answer:

Alborosie3 years ago

5 0

There are zero lone pairs of electrons on the central carbon atom in a Lewis Structure of CHI3. The correct option is b.

Explanation:

Lone pair electrons are those valence electrons of an atom which do not take part in bonding or left after the bonds are formed.

CH $I_{3}$

carbon is the central atom in the compound having 4 valence electrons.

Each iodine molecule has 7 valence electrons.

H has 1 valence electron.

from the Lewis structure of CH $I_{3}$ , it is seen that all four valence electrons of the carbon is involved in bonding with 3 atoms of iodine and 1 atom of hydrogen.

Thus when all valence electrons are involved in bonding no lone pair of electron is found in CH $I_{3}$ that means zero lone pairs of electrons.

The octet of the iodine, carbon and hydrogen gets completed to form the compound.

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A gas has a volume of 340.0 mL at 45.90 oC. What is the new temperature of the gas, in Kelvin, if the volume increased to 550.0

d1i1m1o1n [39]

Answer:

Solution for A gas has a volume of 340.0 mL at 45.90 degree celsius. What is the new temperature of the gas, in kelvin, if the volume increased to 550.0 mL.

Missing: oC. ‎| Must include: oC.

Explanation:

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3 years ago

The activation energy for proline isomerization of a peptide depends on the identity of the preceding residue and obeys Arrheniu

MAVERICK [17]

Answer:

Activation energy of phenylalanine-proline peptide is 66 kJ/mol.

Explanation:

According to Arrhenius equation- $k=Ae^{\frac{-E_{a}}{RT}}$ , where k is rate constant, A is pre-exponential factor, $E_{a}$ is activation energy, R is gas constant and T is temperature in kelvin scale.

As A is identical for both peptide therefore-

$\frac{k_{ala-pro}}{k_{phe-pro}}=e^\frac{[E_{a}^{phe-pro}-E_{a}^{ala-pro}]}{RT}$

Here $\frac{k_{ala-pro}}{k_{phe-pro}}=\frac{0.05}{0.005}$ , T = 298 K , R = 8.314 J/(mol.K) and $E_{a}^{ala-pro}=60kJ/mol$

So, $\frac{0.05}{0.005}=e^{\frac{[E_{a}^{phe-pro}-(60000J/mol)]}{8.314J.mol^{-1}.K^{-1}\times 298K}}$

$\Rightarrow$ $E_{a}^{phe-pro}=65705J/mol=66kJ/mol$ (rounded off to two significant digit)

So, activation energy of phenylalanine-proline peptide is 66 kJ/mol

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3 years ago

How many molecules are there in 5.0g of C2H5OH?

Vilka [71]

About 6.5x10^22 molecules. (5g C2H5OH)x(1 mol C2H5OH/46g C2H5OH)x(6.02x10^23 molecules C2H5OH/1 mol C2H5OH)=(3.01E24)/46=6.5x10^22. Let me know if this helped!

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3 years ago

From gross and specific selection rules below, identify which belongs to the rotational, rotational Raman, vibrational and elect

guajiro [1.7K]

Answer:

Rotational spectroscopy, the dipole moment must change during the transition.

Rotational Raman spectroscopy, molecule must have anisotropic polarizability

Vibrational and electronic spectroscopy, molecule must have permanent dipole moment.

Explanation:

For the vibration rotation spectrum to be observed, it is necessary to change the dipole moment during the vibration.

Raman scattering using an anisotropic crystal gives information about the orientation of the crystal. The polarization of Raman scattering light relative to the crystal, and the polarization of laser light, can be used to determine the orientation of the crystal, provided the crystal structure is known.

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3 years ago

Is Li has 7 valence electrons

jeka94

This is false. The amount of electrons in lithium (Li) is not 7, it is 3. There are 3 electrons in lithium.

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3 years ago

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