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emmainna [20.7K]
2 years ago
5

Find the molar mass of iron (III) nitrate, Fe(NO3)3

Chemistry
1 answer:
spin [16.1K]2 years ago
6 0

Answer:

Hey there are you doing are you doing I will tell you the answer

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PLEASE HELP!!!!
coldgirl [10]

Answer:

1.2 liters.

Explanation:

Focus on the 4th digit: that's the ones column. The 3rd digit is the decimal place, just be sure to round up.

7 0
3 years ago
PLEASE HELP ME, 20 POINTS
Marrrta [24]

Explanations:

<u>Question</u> <u>1:</u> Lithium in 20.00+ g is C. or D., but 25.00+ g is D. which means this is the correct option.

I am unsure of <u>Question</u> <u>2</u>. I don't think it is mole though.

<u>Question</u> <u>3:</u> Boron in 25.00-30.00 g is B. or D., but 25.00 g would be C.

<u>Question</u> <u>4:</u> 2.393 x 1024 atoms of Oxygen is 63.58 mole O. I don't know for sure, but I think this is correct.

<u><em>I am NOT professional. There is a chance I am incorrect. Please reply to me if I've made a mistake.</em></u>

4 0
2 years ago
13. A gas occupies 4.31 liters at a pressure of 0.755 atm. Determine the volume if the
wariber [46]

Answer:

13. 2.60 L.

14. 2.40 L.

Explanation:

We can use the general law of ideal gas: PV = nRT.

where, P is the pressure of the gas in atm.

V is the volume of the gas in L.

n is the no. of moles of the gas in mol.

R is the general gas constant,

T is the temperature of the gas in K.

If n and T are constant, and have different values of P and V:

(P₁V₁) = (P₂V₂)

<em>13. A gas occupies 4.31 liters at a pressure of 0.755 atm. Determine the volume if the  pressure  is increased to 1.25 atm.</em>

P₁ = 0.755 atm, V₁ = 4.31 L.

P₂= 1.25 atm, V₂ = ??? L.

∴ V₂ = (P₁V₁)/(P₂) = (0.755 atm)(4.31 L)/(1.25 atm) = 2.60 L.

<em>14. 600.0 mL of a gas is at a pressure of 8.00 atm. What is the volume of the gas at 2.00  at m.</em>

P₁ = 8.0 atm, V₁ = 600.0 mL.

P₂= 2.0 atm, V₂ = ??? L.

∴ V₂ = (P₁V₁)/(P₂) = (8.0 atm)(600.0 mL)/(2.0 atm) = 2400/0 mL = 2.40 L.

3 0
2 years ago
A balance reads an object A to be 45.1 kg. The balance reads another object B to be 33.46 kg. What is the total weight of both o
postnew [5]

Answer:

The total weight of both object is 78.56 kg.

Explanation:

Given data:

Mass of object A = 45.1 kg

Mass of object B = 33.46 kg

Total weight of object = ?

Solution:

Total weight of both subject must be the sum of weight of object A and B.

Total weight of objects = weight of object A + weight of object B

Now we will put the values of mass of object A and B.

Total weight of objects = 45.1 kg + 33.46 kg

Total weight of objects =78.56 kg

Thus the total weight of both object is 78.56 kg.

7 0
3 years ago
What is the mole ratio to correct balance the reaction below? __KBr + __Ca3N2--&gt; __CaBr2 + __K3N
jonny [76]

Explanation:

3CaBr2 + 2K3N → 6KBr + Ca3N2

7 0
3 years ago
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