<h3>
Answer:</h3>
pH = 8.66
<h3>
Explanation:</h3>
- The pH refers to the acidity or alkalinity of a solution.
- It is calculated by getting the negative logarithm of Hydrogen ions concentration.
In this case;
we are given [OH⁻] as 4.6 x 10^-6 M
We are required to calculate the pH
We need to know that;
pH + pOH = 14
pOH = -log[OH⁻]
To get the pH we can calculate the pOH first,
pOH = -log[4.6 x 10^-6 M]
= 5.34
but, pH + pOH = 14
Therefore, pH = 14 - pOH
= 14 - 5.34
= 8.66
Therefore, the pH of the solution is 8.66
The reaction to form NH3 is : N2 + 3H2-> 2NH3 12,33g NH3 is 12,33/17,03=0,3 =0,724 moles of NH3 moles NH3. So you need 1,5*0,724 = 1,086 moles H2 1,086*2,016 = 2,189 g of H2 is needed ro form 12,33 g NH3
Answer:
1.93 mol Ca
Explanation:
Use Calcium's molar mass to convert g of Ca into mol of Ca.
A crushed garlic will have a lot of flavor when placed in food due to the surface area that is in contact with the food. When we have a large piece of garlic, only the external part touches the food and its full capacity is not used. When we reduce the size of the year by crushing the internal parts that were not in contact with the food, now they will be, in addition, liquids are also released due to the pressure exerted on the garlic and these liquids mix more easily with the food and they give it more flavor. For better understanding we can see the following figure:
Simply to understand it, in the figure, there is a clove of whole garlic represented by the rectangle that will have a height of 3 and a width of 1, the units do not matter in this case. The area that is in contact will be equal to 8, but if we divide the garlic into three equal parts, it will have a contact area greater than 12. Therefore, the more we divide the garlic, the more area it will be in contact with the food and will give it more flavor.
Answer:
Compound A and compound B are constitutional isomers with molecular formula C3H7Cl.
When compound A is treated with sodium methoxide, a substitution reaction predominates. When compound B is treated with sodium methoxide, an elimination reaction predominates.
Explanation:
Constitutional isomers are the one which differs in the structural formula.
When compound A is treated with sodium methoxide, a substitution reaction predominates.
That means sodium methoxide is a strong base and a strong nucleophile.
But when it reacts with primary alkyl halides it forms a substitution product and when it reacts with secondary alkyl halide it forms mostly elimination product.
The reaction and the structures of A and B are shown below: