<span>Solvent is ethyl alcohol.
hope this helps!</span>
<span>Using artificial fertilizers instead of composting will increase water pollution.
So the answer is B.</span>
Answer: oxidizing agent: 
, reducing agent :
Explanation: Oxidation-reduction reaction or redox reaction is defined as the reaction in which oxidation and reduction reactions occur simultaneously.
Oxidation reaction is defined as the reaction in which a substance looses its electrons. The oxidation state of the substance increases.
Reduction reaction is defined as the reaction in which a substance gains electrons. The oxidation state of the substance gets reduced.
For the given reaction:
On reactant side:
Oxidation state of zinc = 0
Oxidation state of copper = +2
On product side:
Oxidation state of zinc = +2
Oxidation state of copper = 0
The oxidation state of copper reduces from +2 to 0, it is getting reduced. The substance which itself gets reduced, oxidizes other and is called as oxidizing agent.Thus acts as oxidizing agent.
The oxidation state of zinc increases from 0 to +2. Thus, it is getting oxidized and it undergoes oxidation reaction.
The substance which itself gets oxidized, reduces other and is called as reducing agent.Thus acts as reducing agent.
Tidal waves are caused by winds and high tides, and a tidal range changes.
The total energy released per gram of methane in the experiment is 119941.33 J/g
<h3>How to determine the change in the temperature of water</h3>
- Initial temperature of water (T₁) = 25 °C
- Final temperature of water (T₂) = 68 °C
- Change in temperature (ΔT) = ?
Change in temperature (ΔT) = T₂ – T₁
Change in temperature (ΔT) = 68 – 25
Change in temperature (ΔT) = 43 °C
<h3>How to determine the heat absorbed by the water</h3>
The absorbed by the water can be obtained as illustrated below:
- Mass of water (M) = s00 g
- Change in temperature (ΔT) = 43 °C
- Specific heat capacity of the water (C) = 4.184 J/gºC
- Heat (Q) =?
Q = MCΔT
Q = 500 × 4.184 × 43
Q = 89956 J
<h3>How to determine the energy released by methane in the experiment</h3>
- Heat absorbed by water = 89956 J
- Percentage of heat absorbed by water = 30%
- Heat released by methane =?
Heat absorbed by water = 30% of heat released by methane
89956 = 30% × heat released by methane
89956 = 0.3 × heat released by methane
Divide both sides by 0.3
Heat released by methane = 89956 / 0.3
Heat released by methane = 299853.33 J
<h3>How to determine the heat released per gram of methane</h3>
- Heat released by methane (Q) = 299853.33 J
- Mass of methane (m) = 2.5 g
- Heat per gram (ΔH) =?
Q = m × ΔH
Divide both sides by m
ΔH = Q / m
ΔH = 299853.33 / 2.5
ΔH =119941.33 J/g
Learn more about heat transfer:
brainly.com/question/6363778
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