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alexgriva [62]
3 years ago
11

The water in a 150-mL flask is poured into a beaker that contains 600 mL of ethyl alcohol. Which substance is the solvent in thi

s mixture?
Chemistry
2 answers:
olga2289 [7]3 years ago
8 0

Answer:

600 mL of ethyl alcohol is the solvent.

Explanation:

The solute is always lesser in amount than the solvent. Here we have 150 ml water and 600 ml ethyl alcohol. So the 150 ml water (lesser in amount) is the solute and 600 ml ethyl alcohol is the solvent. The solute gets dissolved in the solvent to form the solution. The solvent is the one that dissolves the solute to form a homogeneous solution.

borishaifa [10]3 years ago
5 0
<span>Solvent is ethyl alcohol. 

hope this helps!</span>
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The fertilizer ammonium sulfate, (NH4)2SO4, is prepared by the reaction between ammonia (NH3) and sulfuric acid:
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The mass of ammonia required to produce 2.40 × 10⁵ kg of (NH₄)₂SO₄ is 6.18 * 10⁴ Kg of ammonia.

<h3>What mass in kilograms of ammonia are required to produce 2.40 × 10⁵ kg of (NH₄)₂SO₄?</h3>

The mass of ammonia required to produce 2.40 × 10⁵ kg of (NH₄)₂SO₄ is determined from the mole ratio of the reaction.

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4 0
2 years ago
the equilibrium concentrations were found to be [H2O]=0.250 M , [H2]=0.600 M , and [O2]=0.800 M . What is the equilibrium consta
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Keq = 0.217

Explanation:

Let's determine the equilibrium reaction.

In gaseous state, water vapor can be decomposed to hydrogen and oxygen and this is a reversible reaction.

2H₂(g)  + O₂(g)  ⇄  2H₂O (g)         Keq

Let's make the expression for the equilibrium constant

Products / Reactants

We elevate the concentrations, to the stoichiometry coefficients.

Keq = [H₂O]² / [O₂] . [H₂]²

Keq = 0.250² / 0.8 . 0.6² =  0.217

3 0
3 years ago
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