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Sergio [31]
3 years ago
7

What is all the colors in a rainbow​

Chemistry
1 answer:
Lady bird [3.3K]3 years ago
3 0

Answer:

Red, orange, yellow, green, blue, indigo, violet.

Explanation:

You might be interested in
Below are 10 different metric prefixes and their abbreviations. Match them up. :)
Sladkaya [172]

Answer:

1.G → giga  

2.da → deca

3.n → nano

4.m → milli

5.M → mega

6.k → kilo

7.c → centi

8.d → deci

9.h → hecto

10.µ → micro

Explanation:

In descending order:

1.G → giga (1 . 10⁹)  

5.M → mega (1 . 10⁶)

6.k → kilo (1 . 10³)

9.h → hecto (1 . 10²)

2.da → deca (1 . 10¹)

8.d → deci (1 . 10⁻¹)

7.c → centi (1 . 10⁻²)

4.m → milli (1 . 10⁻³)

10.µ → micro  (1 . 10⁻⁶)

3.n → nano (1 . 10⁻⁹)

In example:

1000000 m = 1 Mm

0,000000001 m = 1 nm

7 0
3 years ago
Which statement about endothermic reactions is true?
Y_Kistochka [10]

Answer: The definition of an endothermic reaction is that the products have higher energy than the reactants, resulting in a positive enthalpy of reaction.

Explanation:

5 0
3 years ago
What 3 variables were changed in the pendulum experiment?
Paraphin [41]

Answer:

In this experiment, the period of the pendulum is the dependent variable. There are three independent variables: the pendulum mass, the amplitude of the swing, and the length of the pendulum string.

Explanation:

5 0
3 years ago
A 0.25-mol sample of a weak acid with an unknown Pka was combined with 10.0-mL of 3.00 M KOH, and the resulting solution was dil
Masteriza [31]

Answer : The value of pK_a of the weak acid is, 4.72

Explanation :

First we have to calculate the moles of KOH.

\text{Moles of }KOH=\text{Concentration of }KOH\times \text{Volume of solution}

\text{Moles of }KOH=3.00M\times 10.0mL=30mmol=0.03mol

Now we have to calculate the value of pK_a of the weak acid.

The equilibrium chemical reaction is:

                          HA+KOH\rightleftharpoons HK+H_2O

Initial moles     0.25     0.03        0

At eqm.    (0.25-0.03)   0.03      0.03

                     = 0.22

Using Henderson Hesselbach equation :

pH=pK_a+\log \frac{[Salt]}{[Acid]}

pH=pK_a+\log \frac{[HK]}{[HA]}

Now put all the given values in this expression, we get:

3.85=pK_a+\log (\frac{0.03}{0.22})

pK_a=4.72

Therefore, the value of pK_a of the weak acid is, 4.72

7 0
3 years ago
The kind of energy released when atoms are rearranged to form new bond
Murljashka [212]
The kind of energy released when atoms are rearranged to form new bonds is called Chemical energy.
6 0
3 years ago
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