<span>How much kinetic energy does a 7.2-kg dog need to make a vertical jump of 1.2 m?
</span>Answer:
85 Joule (approx)
Explanation:
Potential energy at highest point
<span><span>P.E = mgh = 7.2 kg × 9.8 m/s2</span>×1.2 m≈85 Joule</span>
The answer is b, gravity and friction are forces.
Hi =D
The answer is D. This is how i figured it out. pV = n R T => if pressure is constant => p = n R T / V = const. => p / n R = T/ V = const. => T / V = const. T1 = 333 K T2 = 533 K V1 = 0.2 m3 T1 / V1 = T2 / V2 => V2 = V1 x T2 / V2 = 0.2 x 533 / 333 = 0.32 m^3.
Hope this is what your looking for.
Answer:
51.96 m/s^-1
Explanation:
a) see the attachment
b) As we know the velocity of the projectile has two component, horizontal velocity v_ox. and vertical velocity v_oy as shown in the figure. At the highest point of the trajectory, the projectile has only horizontal velocity and vertical velocity is zero. Therefore at the highest point of the trajectory, the velocity of the projectile will be
v_ox=v_o*cosФ
=60*cos (30)
= 51.96 m/s^-1