(3x+3)(6x+9) product

120 personas con bronquitis y fumadores, 15 con bronquitis y no fuman, 42 sanos y fumadores, 65 sanos y no fumadores. Si se elig

german

Answer:

Bronchitis is a condition in which the airways of the lungs, called bronchial tubes, become inflamed, causing a cough, often with mucus. Bronchitis can be acute or chronic.

Step-by-step explanation:

6 0

3 years ago

What is the length of the hypotenuse of the triangle below

sdas [7]

Answer:

17

Step-by-step explanation:

Pythagorean Theorem

a^2 + b^2 = c^2

8^2 + 15^2 = c^2

64 + 225 = c^2

c^2 = 289, c = 17

8, 15, 17 is also a common Pythagorean triple.

3 0

2 years ago

Find the missing exponent

zysi [14]

The missing exponent is 22

8 0

2 years ago

Read 2 more answers

The purpose of a statistical quality control chart is to identify when assignable causes of variation have entered the productio

MAXImum [283]

Answer:

TRUE

Step-by-step explanation:

Control charts employ the use of graphical displays to observe and monitor a process which could be either a manufacturing, production or business process to ensure that it is in a sate of control using statistical analysis. This graphical display will enable the visualization of interference or variation dues to certain causes or factors which might creep in to effect an unwanted variation in the production or business process. Hence, with the control chart, these variations would be detected and corrected to ensure that the production proesss is free from unwanted interference as much as possible.

8 0

2 years ago

United Blood Services is a blood bank that serves more than 500 hospitals in 18 states. According to their website, a person wit

Anna11 [10]

Answer:

a) 0.06 = 6% probability that a person has both type O blood and the Rh- factor.

b) 0.94 = 94% probability that a person does NOT have both type O blood and the Rh- factor.

Step-by-step explanation:

I am going to solve this question treating these events as Venn probabilities.

I am going to say that:

Event A: Person has type A blood.

Event B: Person has Rh- factor.

43% of people have type O blood

This means that $P(A) = 0.43$

15% of people have Rh- factor

This means that $P(B) = 0.15$

52% of people have type O or Rh- factor.

This means that $P(A \cup B) = 0.52$

a. Find the probability that a person has both type O blood and the Rh- factor.

This is

$P(A \cap B) = P(A) + P(B) - P(A \cup B)$

With what we have

$P(A \cap B) = 0.43 + 0.15 - 0.52 = 0.06$

0.06 = 6% probability that a person has both type O blood and the Rh- factor.

b. Find the probability that a person does NOT have both type O blood and the Rh- factor.

1 - 0.06 = 0.94

0.94 = 94% probability that a person does NOT have both type O blood and the Rh- factor.

6 0

2 years ago