Question

The length of a rectangle is 3ft less than twice the width, and the area of the rectangle is 77ft^(2). Find the dimensions of the rectangle

Answer 1

Let x = width

2x + 3 = length

Area of rectangle is length times width

x(2x + 3) = 77

2x² + 3x = 77

2x² + 3x - 77 = 0

2x² + 14x - 11x - 77 = 0

2x(x + 7) - 11(x + 7) = 0

(2x - 11)(x + 7) = 0

x = 11/2, - 7

Distance/measurements can't be negative so x = 11/2

The length:

2(11/2) + 3

11 + 3

14

Your width is 11/2 feet and your length is 14 feet.