$1)\\\\\text{Kinetic energy,}\\\\E_k = \dfrac 12 mv^2 \\\\\implies m = \dfrac{2E_k}{v^2} = \dfrac{2\times 4500}{30^2}=10~ kg\\ \\2)\\\\\text{Kinetic energy,}\\\\E_k = \dfrac 12mv^2 \\\\\implies v^2 = \dfrac{2E_k}m\\\\\implies v = \sqrt{\dfrac{2E_k}{m}}=\sqrt{\dfrac{2 \times 320}{\dfrac{20}{9.8}}}= 17.709 ~ ms^{-1}\\\\3)\\\\\text{Kinetic energy,}\\\\E_k=\dfrac 12 mv^2=\dfrac 12 \times 50 \times 10^2=2500 ~J\\\\\\$

$4)\\\\\text{Potential energy,}\\\\E_p =mgh = 5\times 9.8\times 1.5 = 73.5 ~J$

5 0

2 years ago

Four-wheel drive trucks do not stop better on icy

MaRussiya [10]

It would be Newton’s second law of motion

8 0

3 years ago

C.) 65 km = mm Convert

Brums [2.3K]

Hi! 65 km to mm is 65,000,000 mm! Hope this helped you!

6 0

3 years ago

As a car is driven south in a straight line with decreasing speed, fhe acceleration of the car must be

frosja888 [35]

The answer is directed northward. The acceleration will be negative, since the car is decelerating. Thus the power that is slowing it down must be performing in the opposite direction to that which the car is traveling. Or in other words, when speed is lessening, acceleration is in the opposed direction to velocity. The change is CONTRASTING the velocity and so it slows it down.

6 0

3 years ago