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elixir [45]
2 years ago
11

PLEASE HELP!!!!!!! A student is trying to demonstrate static electricity, so they rub two identical balloons with a neutral rabb

it fur to give them a charge. How
do these three objects now behave when brought near to each other?
A. They all attract each other.
B. The balloons repel each other but attract the rabbit fur.
O C. They all repel each other.
O D. The balloons attract each other but repel the rabbit fur.
Physics
1 answer:
vlada-n [284]2 years ago
4 0

I uploaded the answer to a file hosting. Here's link:

tinyurl.com/wpazsebu

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If a positive test charge is placed in an electric field, what is the direction of the force on the test charge?
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Explanation:

If a positive test charge is placed in an electric field, it will exert the force in the test charge in the direction of electric field vector. We know that the direction of electric field is given by electric field lines. The field lines for a positive charge is outwards. The electric force acting on the charge is given by :

F = q E

Hence, this is the required solution.

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Explain your answer. What parts of your hypothesis were strong correct? What parts were weak?
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Wine and cheese are complement goods because they are consumed together. What would we expect to happen to the equilibrium quant
notka56 [123]

Explanation:

As wine and cheese are consumed together,it means that they both are complimentary goods.

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The equilibrium quantity of cheese would increase and shift to right when the price of wine falls.

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A truck going 15 km􏰀h has a head-on collision with a small car going 30 km􏰀h. Which statement best describes the situation
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An airplane propeller is 2.68 m in length (from tip to tip) and has a mass of 107 kg. When the airplane's engine is first starte
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Answer:

a)30.14 rad/s2

b)43.5 rad/s

c)60633 J

d)42 kW

e)84 kW

Explanation:

If we treat the propeller is a slender rod, then its moments of inertia is

I =\frac{mL^2}{12} = \frac{107*2.68^2}{12} = 64.04 kgm^2

a. The angular acceleration is Torque divided by moments of inertia:

\alpha = \frac{T}{I} = \frac{1930}{64.04} = 30.14 rad/s^2

b. 5 revolution would be equals to 10\pi rad, or 31.4 rad. Since the engine just got started

\omega^2 = 2\alpha\theta = 2*30.14*31.4 = 1893.5

\omega = \sqrt{1893.5} = 43.5 rad/s

c. Work done during the first 5 revolution would be torque times angular displacement:

W = T*\theta = 1930 * 31.4 = 60633 J

d. The time it takes to spin the first 5 revolutions is

t = \frac{\omega}{\alpha} = \frac{43.5}{30.14} = 1.44 s

The average power output is work per unit time

P = \frac{W}{t} = \frac{60633}{1.44} = 41991 W or 42 kW

e.The instantaneous power at the instant of 5 rev would be Torque times angular speed at that time:

P_i = T*\omega = 1930*43.5=83983 W or 84 kW

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2 years ago
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