3 years ago

Help me plsssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssss

Mathematics

1 answer:

dmitriy555 [2]3 years ago

7 0

Answer:

The full answer in the media.Good luck!

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please help John's age increased by 11 is 5 less than 5 times his age. How old is he? If x represents John's age, which of the f

Keith_Richards [23]

So x is John's age.
We can solve this problem by working backwards.
Since it's 5 times his age, we first do 5x.
And then since it's five less, we move on to 5x - 5
And then we add the John's age is increased by 11: 5x - 5 = x + 11
I hope this helped :)
(It should be the second one you listed)

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2 years ago

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mrs_skeptik [129]

400, if you can buy 4 tickets for $6 you can buy 400 for $600

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2 years ago

Plz help i did it now

puteri [66]

56*4/5

=11.2*4

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that is the answer

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2 years ago

What is the best estimate of the area of the figure on the grid if each square has side lengths of 1 inch?

Phoenix [80]

Answer:

C) 29 square inches

Step-by-step explanation:

5 x 5 = 25

Triangles = 0.5

25 + 2 = 27

27 + (4 x 0.5)

27 + 2 =29

~~Thanks,

Sanjith U.

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2 years ago

Read 2 more answers

A programmer plans to develop a new software system. In planning for the operating system that he will use, he needs to estimat

Contact [7]

Answer: a. n= 1068

b. n= 164

Step-by-step explanation:

The formula to find the sample size :

$n=p(1-p)(\dfrac{z^{*}}{E})^2$

, where p=prior population proportion , z* = critical z-value and E = Margin of error.

Here , let p=proportion of computers that use a new operating system.

Given : Confidence level = 95%

i.e. z* = 1.96 [by z-table]

Margin of error : E = 3% =0.03

a. If p is unknown , then we assume p=0.5

Then, $n=(0.5)(1-0.5)(\dfrac{1.96}{0.03})^2=1067.11111\approx1068$

i.e. n= 1068

b. p=0.96

Then, $n=(0.96)(1-0.96)(\dfrac{1.96}{0.03})^2=163.908266667\approx164$

i.e. n= 164.

6 0

3 years ago