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Sloan [31]
3 years ago
12

A piece of art weighing 30 pounds is hung from two wires as shown below. Each wire is supporting half of the weight of the pictu

re. However, since the wires extend out at an angle, they are also imparting force towards the left and right. Therefore, the force on each wire is greater than 15 pounds. Look at the diagram above with the vectors. Use trigonometry to find ||→ux||and ||→vx||.
||→ux||=____  pounds    ||→vx||= ___ pounds    What is the total force (in pounds) exerted on each wire?
||→u||= ____pounds    ||→v||=  ____pounds   ​​​​

Mathematics
1 answer:
fredd [130]3 years ago
5 0

Answer:

30 pounds + 15 pounds is 45 pounds is your total force

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4 years ago
Se quiere construir un muro de 4 m de alto, 12 m de largo y 10 cm de espesor. ¿Cuántos ladrillos de 8 cm de alto, 20 cm de largo
Llana [10]

Answer:

3000

Step-by-step explanation:

Let's start by finding the volume of the wall. The volumen of the wall can be considered as the volume of a rectangular prism. The volume of a rectangular prism is given by:

V_w=w*l*h\\\\Where:\\\\w=Width=10cm=0.1m\\l=Length=12m\\h=Height=4m

So the volume of the wall is:

V_w=0.1*12*4=4.8m^3

Now, we can find the volume of the brick using the same method since a brick can be considered as a rectangular prism as well:

V_b=w*l*h\\\\For\hspace{3}the\hspace{3}brick\\\\w=10cm=0.1m\\l=20cm=0.2m\\h=8cm=0.08m

Hence:

V_b=(0.1)*(0.2)*(0.08)=0.0016m^3

In order to know how many bricks are required to build the wall, we just need to fill the wall volume with the number of bricks of this volume. So:

V_w=nV_b\\\\Where\\\\n=Number\hspace{3}of\hspace{3}bricks

Solving for n:

n=\frac{V_w}{V_b} =\frac{4.8}{0.0016} =3000

Therefore, we need 3000 bricks to build that wall.

Translation:

Comencemos por encontrar el volumen del muro. El volumen del muro puede considerarse como el volumen de un prisma rectangular. El volumen de un prisma rectangular viene dado por:

V_w=w*l*h\\\\Donde:\\\\w=Espesor=10cm=0.1m\\l=Largo=12m\\h=Alto=4m

Entonces el volumen del muro es:

V_w=0.1*12*4=4.8m^3

Ahora, podemos encontrar el volumen del ladrillo utilizando el mismo método, ya que un ladrillo también puede considerarse como un prisma rectangular:

V_b=w*l*h\\\\Para\hspace{3}el\hspace{3}ladrillo\\\\w=10cm=0.1m\\l=20cm=0.2m\\h=8cm=0.08m

Por lo tanto:

V_b=(0.1)*(0.2)*(0.08)=0.0016m^3

Para saber cuántos ladrillos se requieren para construir el muro, solo necesitamos llenar el volumen del muro con la cantidad de ladrillos de este volumen. Entonces:

V_w=nV_b\\\\Donde\\\\n=Numero\hspace{3}de\hspace{3}ladrillos

Resolviendo para n:

n=\frac{V_w}{V_b} =\frac{4.8}{0.0016} =3000

Por lo tanto, necesitamos 3000 ladrillos para construir ese muro.

4 0
4 years ago
Please Help! 39 and 40 please!!! :D
Pavel [41]

Answer:

Look below.

Step-by-step explanation:

39.

10+ = 149 times x

3 - 9  = 143 times x

40.

2(w times 1.5 + w)

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4 years ago
a metal alloy weighing 3 mg and containing 40% copper is melted and mixed with 2 mg of pure copper. what percent of the resultin
Oduvanchick [21]
64%, because 40% of 60% is 24%, and 2 mg of pure copper is 40% of the overall alloy, so add 24 and 40
4 0
3 years ago
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