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Tom [10]
2 years ago
15

All of the following are equivalent EXCEPT x < 2 x - 2 < 4 2x < -4 x - 2 < -4

Mathematics
1 answer:
Vlad [161]2 years ago
4 0

Answer:

solution

x<2,2x<-4,x-2<-4 are equvalent

but x-2<4 is not

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lutik1710 [3]
The answer is 6 positive tiles.
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3 years ago
You collect a total of $75 in donations from three people. The three donations are in the ratio 4 to 4 to 7. How much is each of
worty [1.4K]
Each smaller donation was for $20 The largest donation was $15 greater than the smaller donation. First, determine the size of each donation. Since they are in a ratio of 4:4:7, it's easiest to add the ratios together (4+4+7) = 15. Then divide the total donation by that sum (75/15) = 5. Finally, multiply 5 by each of the ratios. 5 * 4 = 20, 5 * 4 = 20, and 5 * 7 = 35 So the 2 smaller donations were $20 each, and the largest donation was for $35. The largest donation was $35 - $20 = $15 larger than one of the smaller donations.
7 0
3 years ago
Winston has just gone grocery shopping. The mean cost for each item in his bag was $2.71. He bought a total of 9 items, and the
sukhopar [10]

The cost of the 9th item is  $3.94

Since the mean cost for the 9 items in his bag was $2.71. Then, the total cost will be: = 9 × $2.71 = $24.39

In order to get the price of the 9th item, we have to calculate the price of all the 8 items given which will be:

$2.01 + $2.20 + $2.68 + $3.59 + $3.12 + $1.64, + $1.75 + $3.46 = $20.45

Therefore, the cost of the 9th item will be:

= $24.39 - $20.45

= $3.94

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brainly.com/question/24562826

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2 years ago
How do you solve the photo below
VikaD [51]

Answer:

6

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
I NEED THIS ASAP, PLEASE HELP!!!
WINSTONCH [101]

Answer: 22.5 ; 5 ; 14

Step-by-step explanation:

Given the dataset:

{20,22,23,24,26,26,28,29,30}

The lower quartile (Q1) = 1/4(n + 1)th term

Where n = number of observations, n = 9

Q1 = 1/4 (9 + 1)th term

Q1 = 1/4(10) = 2.5

We average the 2nd and 3rd term:

(22 + 23) / 2

45 / 2 = 22.5

B) The interquartile range(IQR) of the dataset :

{62,63,64,65,67,68,68,68,69,74}

IQR = Q3 - Q1

The lower quartile (Q1) = 1/4(n + 1)th term

Where n = number of observations, n = 10

Q1 = 1/4 (10 + 1)th term

Q1 = 1/4(11) = 2.75 term

We take the average of the 2nd and 3rd term:

(63 + 64) / 2

45 / 2 = 63.5

The upper quartile (Q3) = 3/4(n + 1)th term

Where n = number of observations, n = 10

Q3 = 3/4 (10 + 1)th term

Q3 = 3/4(11) = 8.25 term

We take the average of the 8th and 9th term:

(68 + 69) / 2

137 / 2 = 68.5

IQR = Q3 - Q1

IQR = 68.5 - 63.5

IQR = 5

C) give the dataset :

{7,8,8,9,10,12,13,15,16}

The upper quartile (Q3) = 3/4(n + 1)th term

Where n = number of observations, n = 9

Q3 = 3/4 (9 + 1)th term

Q3 = 3/4(10) = 7.5 term

We take the average of the 7th and 8th term:

(13 + 15) / 2

28 / 2 = 14

7 0
3 years ago
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