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Elodia [21]
3 years ago
15

Which organisms perform photosynthesis in their cells

Chemistry
1 answer:
balu736 [363]3 years ago
3 0
A:Autotrophs
Explanation: Heterotrophs get their energy by eating Autotrophs. Not by photosynthesis.
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Using a chemical equation to find moles of product from moles...
kaheart [24]

Answer: 0.600 moles

Balanced eqn for decomposition of the rocket fuel:

2 NH4ClO4 (s) ----> N2 (g) + Cl2 (g) + 2 O2 (g) + 4 H2O (g)

Since, 2 moles of NH4ClO4 produces 2 moles of O2 gas, this means that 0.6 moles of NH4ClO4 will produce 0.6 moles of O2 gas

7 0
2 years ago
What is the chemical formula of the ionic compound sodium acetate?
valentina_108 [34]

Answer:

The correct answer is option A

4 0
2 years ago
Explain why non-metals tend to be poor conductors using the term electronegativity.
Marrrta [24]

Explanation:

Components that throughout chemical processes appear to acquire electrons to achieve anions are considered non-metals. These were all elements which are electronegative. Those who are – anti conductors of electricity and heat, fragile and disadvantaged.

8 0
3 years ago
Calculate ΔHrxn for the following reaction: Fe₂O₃(s)+3CO(g)→2Fe(s)+3CO₂(g) Use the following reactions and given ΔH′s. 2Fe(s)+3/
ExtremeBDS [4]

Answer : The enthalpy change of reaction is -23.9 kJ

Explanation :

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.

The given final reaction is,

Fe_2O_3(s)+3CO(g)\rightarrow 2Fe(s)+3CO_2(g)    \Delta H=?

The intermediate balanced chemical reaction will be,

(1) 2Fe(s)+\frac{3}{2}O_2(g)\rightarrow Fe_2O_3(s)    \Delta H^o_1=-824.2kJ

(2) CO(g)+\frac{1}{2}O_2(g)\rightarrow CO_2(g)    \Delta H^o_2=-282.7kJ

First we will reverse the reaction 1 and multiply equation 2 by 3 then adding both the equation, we get :

(1) Fe_2O_3(s)\rightarrow 2Fe(s)+\frac{3}{2}O_2(g)    \Delta H^o_1=+824.2kJ

(2) 3CO(g)+\frac{3}{2}O_2(g)\rightarrow 3CO_2(g)    \Delta H^o_2=3\times (-282.7kJ)=-848.1kJ

The expression for final enthalpy is,

\Delta H=\Delta H^o_1+\Delta H^o_2

\Delta H=(+824.2kJ)+(-848.1kJ)

\Delta H=-23.9kJ

Therefore, the enthalpy change of reaction is -23.9 kJ

7 0
3 years ago
Bruh Im 4th on the leaderboard How is this possible
forsale [732]

Answer:

I guess you just answered a lot of questions

Explanation:

Thanks for the points btw :)

4 0
3 years ago
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