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andrew-mc [135]
3 years ago
12

PLEASE HELP 50 POINTS A really colorful reaction is the synthesis reaction of aluminum and iodine, often called the “Purple Haze

” reaction. What is the greatest amount of AlI3 (in grams) that can be made from 25.0 g of Al and 50.0 g of I2? What is the limiting reactant? What is the excess reactant, and how many grams of it are left over? 2 Al + 3 I2 → 2 AlI3
Chemistry
1 answer:
marysya [2.9K]3 years ago
7 0

Answer:

I know that the limited reactant Al.

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If the methane contained in 2.50 L of a saturated solution at 25 ∘C was extracted and placed under STP conditions, what volume w
Sunny_sXe [5.5K]

116.6 x 10^{ -3} is the volume of methane contained in 2.50 L of a saturated solution at 25 ∘C that was extracted and placed under STP conditions.

<h3>What is an ideal gas equation?</h3>

The ideal gas law (PV = nRT) relates to the macroscopic properties of ideal gases. An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).

The solubility of methane in water at 25 degrees Celcius is 1.3 x 10^{ -3} M. It implies   1.3 x 10^{ -3} moles of methane are dissolved in one litre of water.

The number of moles of methane in 4 L of water can be calculated as follows:

Moles of methane = \frac{1.3 . 10^{ -3} }{1L} x\frac{4L}{1L}

Moles of methane = 5.2 x 10^{ -3}

STP refers to standard temperature and pressure. Under STP conditions, the temperature of the substance is  0 degrees celcius and its pressure is 1 atm.

An ideal gas is an imaginary gas comprising of a large number of randomly moving particles and the motion between such articles is considered to be perfectly elastic. The ideal gas equation describes the relationship between pressure, volume, temperature and number of moles of a gas.

The expression for ideal gas equation is as follows:

PV=nRT, where n is the moles and R is the gas constant. Then divide the given mass by the number of moles to get molar mass.

Given data:

P= 1 atm

V= ?

R= 0.082057338 \;L \;atm \;K^{-1}mol^{-1}

T=273K

n=?

Putting value in the given equation:

\frac{PV}{RT}=n

5.2 x 10^{ -3} = \frac{1 \;atm\; X \;V}{0.082057338 \;L \;atm \;K^{-1}mol^{-1} X 273}

V= 116.6 x 10^{ -3}

Hence, 116.6 x 10^{ -3} is the volume of methane contained in 2.50 L of a saturated solution at 25 ∘C was extracted and placed under STP conditions.

Learn more about the ideal gas here:

brainly.com/question/27691721

#SPJ1

4 0
2 years ago
How many liters would 4.56 mol sulfur dioxide occupy at STP?
algol13

The volume of Sulfur dioxide-SO₂ at STP : = 102.144 L

<h3>Further explanation</h3>

Given

4.56 mol Sulfur dioxide-SO₂

Required

The volume

Solution

Conditions at T 0 ° C and P 1 atm are stated by STP (Standard Temperature and Pressure). At STP, Vm is 22.4 liters/mol.

so for 4.56 mol :

= 4.56 x 22.4 L

= 102.144 L

4 0
3 years ago
A student reacts 5.0 g of sodium with 10.0 g of chlorine and collect 5.24 g of sodium chloride. What is the percent yield of thi
Ede4ka [16]

Answer: The percent yield of this combination reaction is 41.3 %

Explanation : Given,

Mass of Na = 5.0 g

Mass of Cl_2 = 10.0 g

Molar mass of Na = 23 g/mol

Molar mass of Cl_2 = 71 g/mol

First we have to calculate the moles of Na and Cl_2.

\text{Moles of }Na=\frac{\text{Given mass }Na}{\text{Molar mass }Na}

\text{Moles of }Na=\frac{5.0g}{23g/mol}=0.217mol

and,

\text{Moles of }Cl_2=\frac{\text{Given mass }Cl_2}{\text{Molar mass }Cl_2}

\text{Moles of }Cl_2=\frac{10.0g}{71g/mol}=0.141mol

Now we have to calculate the limiting and excess reagent.

The balanced chemical equation will be:

2Na+Cl_2\rightarrow 2NaCl

From the balanced reaction we conclude that

As, 2 mole of Na react with 1 mole of Cl_2

So, 0.217 moles of Na react with \frac{0.217}{2}=0.108 moles of Cl_2

From this we conclude that, Cl_2 is an excess reagent because the given moles are greater than the required moles and Na is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of NaCl

From the reaction, we conclude that

As, 2 mole of Na react to give 2 mole of NaCl

So, 0.217 mole of HCl react to give 0.217 mole of NaCl

Now we have to calculate the mass of NaCl

\text{ Mass of }NaCl=\text{ Moles of }NaCl\times \text{ Molar mass of }NaCl

Molar mass of NaCl = 58.5 g/mole

\text{ Mass of }NaCl=(0.217moles)\times (58.5g/mole)=12.7g

Now we have to calculate the percent yield of this reaction.

Percent yield = \frac{\text{Actual yield}}{\text{Theoretical yield}}\times 100

Actual yield = 5.24 g

Theoretical yield = 12.7 g

Percent yield = \frac{5.24g}{12.7g}\times 100

Percent yield = 41.3 %

Therefore, the percent yield of this combination reaction is 41.3 %

4 0
3 years ago
Three other application of Bernoulli's principle ?
Makovka662 [10]
<h2><u>Answer:</u></h2>

Bernoulli's Theorem in a general sense relates the weight, speed, and rise in a moving fluid (liquid or gas), the compressibility and consistency (internal grinding) of which are insignificant and the flood of which is predictable, or laminar.

(1): We can discover the speed of Efflux of a fluid.

This is given by v= sqrt (2gh), where the fluid is turning out from an opening in a vessel at profundity h from free fluid surface. This condition is known as Torricelli's hypothesis.

(2): Vena Contracta: The fluid stream from gap contracts at a separation minimal outside the opening to a neck, called Vena Contracta.

The territory of cross-segment of a fly is littler than a zone of opening. From this reality, we can discover the coefficient of withdrawal.

(3) : Bernoulli's standard is utilized in the development of Venturimeter, an instrument for estimation of measure of a stream of a fluid through a pipe.

7 0
3 years ago
Ayyyy Country <br> #12 ⚾<br> how u doin?
mr_godi [17]

Explanation:

you look like a mohammed. im good, hbu?

6 0
3 years ago
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