Answer:
1.0M HCl is the concentration of the acid
Explanation:
Based on the reaction, 1 mole of NaOH reacts per mole of HCl. That means the moles added of NaOH in the neutralization = Moles of HCl in the solution. With the moles and the volume in Liters we can find the molar concentration of HCl
<em>Moles NaOH = Moles HCl:</em>
25.0mL = 0.025L * (2.0moles / L) = 0.050moles HCl
<em>Molarity:</em>
0.050moles HCl / 0.0500L =
<h3>1.0M HCl is the concentration of the acid</h3>
30 degrees from the mirror's surface
pretty sure It's correct and if it is then your welcome
Explanation:
Compound: a substance that is made up of more than 1 type of atom bonded together Example: H2O
Mixture: combination of two or more elements or compounds not chemicaly bonded together. example: Sugar and salt in one container
elements pure substance of an atom. Example: hydrogen
Answer:
10.88 g
Explanation:
We have:
[CH₃COOH] = 0.10 M
pH = 5.25
Ka = 1.80x10⁻⁵
V = 250.0 mL = 0.250 L
The pH of the buffer solution is:
(1)
By solving equation (1) for [CH₃COONa*3H₂O] we have:
![[CH_{3}COONa*3H_{2}O] = 10^{-0.495} = 0.32 M](https://tex.z-dn.net/?f=%5BCH_%7B3%7DCOONa%2A3H_%7B2%7DO%5D%20%3D%2010%5E%7B-0.495%7D%20%3D%200.32%20M)
Hence, the mass of the sodium acetate tri-hydrate is:
![m = moles*M = [CH_{3}COONa*3H_{2}O]*V*M = 0.32 mol/L*0.250 L*136 g/mol = 10.88 g](https://tex.z-dn.net/?f=m%20%3D%20moles%2AM%20%3D%20%5BCH_%7B3%7DCOONa%2A3H_%7B2%7DO%5D%2AV%2AM%20%3D%200.32%20mol%2FL%2A0.250%20L%2A136%20g%2Fmol%20%3D%2010.88%20g)
Therefore, the number of grams of CH₃COONa*3H₂O needed to make an acetic acid/sodium acetate tri-hydrate buffer solution is 10.88 g.
I hope it helps you!