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LenKa [72]
4 years ago
7

Give the half reaction method of basic medium mno4 - + I give out mno2 + I2​

Chemistry
1 answer:
Andreas93 [3]4 years ago
7 0
Mono 22hope this helps
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Which of the following represents the chemical reaction of aluminum and ferric oxide to produce iron and aluminum oxide? A. alum
DerKrebs [107]
Option A is correct. Over all reaction is as follow,

                             Fe₂O₃ (s) + 2 Al (s) → 2 Fe (s) + Al₂O₃ <span>(s)
</span>Explanation:
                   Here we are having two metals, Iron and Aluminium. Aluminium is very reactive than Iron and it is above Iron in the reactivity series. 
                   This reaction has great importance in welding Iron on other metals, like welding Railway tracks. When Ferric Oxide is mixed with Aluminium metal and a spark is given, a vigorous exothermic reaction starts. The temperature reaches approximately 2000°C and Iron with melting point 1535 °C melts and is used for welding purpose. Such type of reaction is called as Thermite Reaction.
7 0
3 years ago
Calculate the number of moles of gas that occupy a 16L container at a pressure of 3 atm and a temperature of 48oC
kondaur [170]

Answer:

1.81

Explanation:

3*16=n(0.0821)(48+273)

7 0
3 years ago
Rank the following solutions in order of increasing acidity (least acidic to most acidic): I: [H3O+] = 1x10−5 II: [OH−] = 1x10−1
kozerog [31]

Answer: option C) II < III < I

i.e [OH−] < [H3O+] < I

Explanation:

First, obtain the pH value of I and II, then compare both with III.

For I

Recall that pH = -log (H+)

So pH3O = -log (H3O+)

= - log (1x10−5)

= 4

For II

pOH = - log(OH-)

= - log(1x10−10)

= 9

For III

pH = 6

Since, pH range from 1 to 14, with values below 7 to be acidic, 7 to be neutral, above 7 to be alkaline: then, 9 < 6 < 4

Thus, the following solutions from least acidic to most acidic is II < III < I

6 0
3 years ago
A 75.0 mL volume of 0.200 M NH3 (Kb=1.8*10^-5) is titrated with 0.500 M HNO3. Calculate the pH after the addition of 25.0 mL of
Murljashka [212]
 <span>pKb = - log 1.8 x 10^-5 = 4.7 
moles NH3 = 0.0750 L x 0.200 M=0.0150 
moles HNO3 = 0.0270 L x 0.500 M= 0.0135 
the net reaction is 
NH3 + H+ = NH4+ 
moles NH3 in excess = 0.0150 - 0.0135 =0.0015 
moles NH4+ formed = 0.0135 
total volume = 75.0 + 27.0 = 102.0 mL = 0.102 L 
[NH3]= 0.0015/ 0.102 L=0.0147 M 
[NH4+] = 0.0135/ 0.102 L = 0.132 M 

pOH = pKb + log [NH4+]/ [NH3]= 4.7 + log 0.132/ 0.0147=5.65 
pH = 14 - pOH = 14 - 5.65 =8.35 

I hope my answer has come to your help. Thank you for posting your question here in Brainly.
</span>
3 0
4 years ago
To get dna out of a living cell, how many cell membranes would you need to pierce or remove?
Ivenika [448]
DNA extraction from living cell
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Removal of cell membrane
                                              In order to remove cell membrane some detergents are applied followed by physical lysis through vertex.when the first cell membrane is pierced it is removed through centifugation by adding phenol and chloroform.

Removal of nuclear membrane
                                                    Proteinase enzyme is added which help in rupturing of nuclear membrane and removal of histone protein from DNA. Then RNAse is added to remove RNA from DNA. 
7 0
3 years ago
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