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Dominik [7]
3 years ago
12

The moist bread becomes mouldy after a few days when it is left in a container with a cover. Which of the following conditions f

avour the growth of the fungus?
Physics
1 answer:
malfutka [58]3 years ago
3 0

Answer: Moisture and food (bread)

Explanation:

Mould grows best in humid, damp air/wet conditions.

Since the bread is moist it will provide humidity for the mould as well as food.

A container with a cover would not be a favoring condition as mould needs oxygen to grow and survive.

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If a 580 N net force acts on a 40 kg what will the acceleration of the car be
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Answer:

I think u have to do 580N times 40KG

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A 35 kg chair is lifted 5M off the ground. what is the potential energy?
patriot [66]

Answer:

mass × gravity ×height. so....that.. Ep = mgh. Ep= 35×9.8×5. Ep = 1715.

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8 0
2 years ago
You place a 3.0-m-long board symmetrically across a 0.5-m-wide chair to seat three physics students at a party at your house. If
wlad13 [49]

Answer:

  • between locations that are 14 cm outboard of the chair edges
  • the weightless board is centered and end sitters are 25 cm from the ends

Explanation:

We can assume the .5 m-wide chair means that it is comfortable for each student to sit 0.25 m from the end of the board. If the board is centered on the chair, then each student is 1 m from the edge of the chair.

When Dan and Tahreen are seated on the board, their center of mass is ...

  (50 kg×2.5 m)/(50 kg +67 kt) = 1.068 m

to the right of the position where Dan is seated. Since this location is over the chair, the board is stable.

Komila can sit as much as x distance from the chair toward Dan, where ...

  67(1) +54(x) = 50(1.5)

  x = 8/54 ≈ 0.148 . . . . meters

Or, Komila can sit as much as x distance from the chair toward Tahreen, where ...

  67(1.5) = 54(x) +50(1)

  x = 50.5/54 ≈ 0.935 . . . . meters

<u>Scenario 1</u>

Assuming the (weightless) board is centered on the chair, Komila can sit anywhere between 14.8 cm left of the chair and 93.5 cm right of the chair and the board will remain stable. Sitting on the board centered on the chair is a suitable location. The two students sitting on the ends must become (and stay) seated at the same time. They both must be seated 0.25 m from the end of the board for the other dimensions to remain valid.

<u>Scenario 2</u>

Assuming the (weightless) board is located so its left end is 1.068 m from the chair, and Dan and Tahreen are seated 0.25 m from the ends of the board, Komila can sit anywhere within (117/54×.25 m) = 0.54 m of the chair and the board will remain stable. Again, sitting centered on the chair is a suitable location.

__

There does not appear to be any location where Komila can sit and have the board remain stable with only Dan or Tahreen seated on one end (assuming a width of 0.5 m for each sitter).

_____

<em>Comment on the question</em>

For the board to remain stable, the sum of moments about either edge of the chair must tend to rotate the board toward the chair. This sum will depend on the locations of the sitters relative to each edge of the chair, so there is significant freedom in choosing locations. To make the problem tractable, we have made some specific assumptions about where the board is and what the locations of the sitters might be. YMMV

3 0
4 years ago
Write one general properties of non contact force​
Gekata [30.6K]

Answer:    Gravitational force between the two masses does not depend on the medium separating two masses.

3 0
3 years ago
John pushes his bed to the left overcoming the force of friction. On the free-body diagram below, which force represents the fri
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Answer:

<em>Force B</em>

Explanation:

<u>Friction Force </u>

It's a force that appears when an object is tried to move on a rough surface. There are two cases: when the object is at rest, we have the friction static coefficient and when the object is already moving, we have the dynamic coefficient. The static coefficient is usually greater than the second because it's harder to overcome the friction when the object is at rest.

We are told that John pushes the bed to the left with enough force to overcome the force of friction. If the movement is intended to be to the left side, the friction force appears to the right, since it always opposes to the movement. Thus the force B is the one who represents the friction force in this situation

6 0
4 years ago
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