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Margaret [11]
3 years ago
15

18)

Physics
1 answer:
iris [78.8K]3 years ago
7 0

Answer:

The answer,  because i gotta

Explanation:

finish a challenge

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In the context of depth perception, which of the following is a monocular cue?
olga55 [171]
Hello there.

<span>In the context of depth perception, which of the following is a monocular cue?

</span><span>(C) Convergence
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3 years ago
You own a high speed digital camera that can take a picture every 0.5 seconds. You decide to take a picture every 0.5 seconds of
Vesnalui [34]

-- There is no need to develop the pictures.  They are available immediately in a digital camera.

-- There is no change in the teacher from one picture to the next.

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2 years ago
A scientist testing to see how a cat “always” lands on their feet drops a cat upside down out of a third story window at a heigh
makkiz [27]

<u>Answer: </u>

Cat has 2.02 seconds to right itself.

<u>Explanation: </u>

Initial height of cat from ground = 20 meter.

We have equation of motion , s= ut+\frac{1}{2} at^2, s is the displacement, u is the initial velocity, a is the acceleration and t is the time.

In this the velocity of cat in vertical direction = 0 m/s, acceleration = acceleration due to gravity =  9.8 m/s^2, we need to calculate time when s = 20 meter.

Substituting

20=0*t+\frac{1}{2} *9.8*t^2\\ \\ t = 2.02 seconds

So, cat has 2.02 seconds to right itself.

7 0
3 years ago
How are sound waves different from the ripples that spread across water?​
prisoha [69]

Answer:

.

Explanation:

Sound waves are caused by vibration ripples in water are caused by disturbance in the molecules

6 0
2 years ago
Read 2 more answers
A 5.50-kg object is hung from the bottom end of a vertical spring fastened to an overhead beam. The object is set into vertical
iris [78.8K]

Answer:

17.71N/m

Explanation:

The period of the spring is expressed according to the expression;

T = 2 \pi \sqrt{\frac{m}{k} } \\

m is the mass of the object

k is the force constant

Given

m = 5.50kg

T = 3.50s

Substitute into the formula;

T = 2 \pi \sqrt{\frac{m}{k} } \\3.5 = 2 (3.14) \sqrt{\frac{5.5}{k} } \\3.5 = 6.28 \sqrt{\frac{5.5}{k} } \\\frac{3.5}{6.28} =  \sqrt{\frac{5.5}{k} } \\0.557 = \sqrt{\frac{5.5}{k} } \\square \ both \ sides\\0.557^2 = (\sqrt{\frac{5.5}{k} })^2 \\0.3106 = \frac{5,5}{k}\\k = \frac{5.5}{0.3106}\\k =  17.71N/m

Hence the force constant of the spring is 17.71N/m

4 0
3 years ago
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