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oksano4ka [1.4K]
4 years ago
8

How to do this question

Physics
1 answer:
andre [41]4 years ago
8 0

Answer:

1 m/s^2

Explanation:

V = U + at

20 = 15 + a(5)

5a = 5

acceleration = <u>1 m/s^2</u>

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When you changed from low to high power, how did the change affect the working distance of the lens?
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An electron with a speed of 1.7 × 107 m/s moves horizontally into a region where a constant vertical force of 4.9 × 10-16 N acts
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 y = 77.74 10⁻⁵ m

Explanation:

For this exercise we can use Newton's second law

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        a = F / m

        a = 4.9 10⁻¹⁶ / 9.1 10⁻³¹

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Now let's use kinematics to find the time it takes to move the

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On the x axis

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            t = 29 10⁻³ / 1.7 10⁷

            t = 17 10⁻¹⁰ s

Now we can look for vertical distance at this time.

            y = v_{oy} t + ½ a t²

            y = 0 + ½ 0.538 10¹⁵ (17 10⁻¹⁰)²

            y = 77.74 10⁻⁵ m

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