Answer:
There were 7 small boxes and 14 large boxes shipped.
Step-by-step explanation:
This problem may be solved by a system of equations:
I am going to say that:
x is the number of small boxes used
y is the number of large boxes used
There were twice as many large boxes shipped as small boxes shipped
This means that y = 2x
Each small box of paper weighs 45 pounds and each large box of paper weighs 80 pounds. The total weight of all boxes was 1435 pounds.
This means that 45x + 80y =1435
So we have to solve the following system:
y=2x
45x + 80y =1435
45x + 80 (2x) = 1435
205x = 1435
x= 1435/205
x=7
y=2x= 2(7) = 14
There were 7 small boxes and 14 large boxes shipped.
H(arold) = 2 + 2*K(enneth)
H = 2 + 2K
H + K = 38
Substitution:
2 + 2K + K = 38
3K = 36
K = 12
Kenneth solved 12 problems and Harold solved (2(12) + 2 = 24 + 2 =) 26 problems
Answer:21
Step-by-step explanation:
<u>cu u=-(5-12)=-7 c=-3 -7(-3)=21</u>
The scale is 4 ft.per inch. (48 in. to every one inch)
To start off, we know that for every 1.5 inch, there is 6ft. (72 inches)
Divide 72 by 1.4 and get 48 inches by 1
or simple take 6ft and divide it by 1.5 inch.
A cone could be sliced parallel to one of its faces to get a circle.
