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viva [34]
3 years ago
5

What percent of 58 is 118.2? Round to the nearest tenth of a percent.

Mathematics
1 answer:
Luden [163]3 years ago
4 0

Answer: 203.8 percent

Step-by-step explanation:

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On the farm, rather than use money, they exchange animals. The exchanges are as follows: 4 bunnies = 3 chickens, 5 chickens = 2
Radda [10]

We have to trade 5 bunnies for a donkey.

Solution:

To calculate how many bunnies could be exchanged for a donkey, we have to multiply the exchange rates of each animal/bird.

One bunny = 3/4 chickens (0.75 chicken),

One chicken = 2/5 pigs (0.4 pigs)

One pig = 2/3 donkeys (0.67 donkeys).

On multiplying all of the above rates we get,

0.75*0.4*0.67=0.2

Since we now know a bunnies worth is 0.2 donkey

Therefore, (1/0.2=5) 5 bunnies to trade for a donkey.

4 0
3 years ago
5 1/2 <br> -<br> 3 3/4<br> ______
eimsori [14]
So first you want to convert both to have the same denominator.

5 1/2 - 3 3/4

To:

5 2/4 - 3 3/4

Now, to make it easier for me, I would convert both to an improper fraction.

5 2/4 -> 22/4

3 3/4 -> 15/4

So now you can just do,

22/4 - 15/4,

which is just 7/4.

This in mixed number form is 1 3/4.
5 0
3 years ago
Read 2 more answers
0.26 - 106-100 - 106
Ksenya-84 [330]

Answer:

-311.74

Step-by-step explanation:

3 0
2 years ago
Latrell is comparing two job opportunities one job will pay $12 an hour and he will work 40 hour a week. The other one pays an a
Nata [24]

To compare these two jobs, you need to have a common point. In this problem, you have to solve for the annual salary of the first job and compare it with the annual salary of the second job which is already given.

$12 per hour x 40 hours per week x 48 weeks in a year = $23,040

First job’s annual salary is $23,040

Second job’s annual salary is $22,000

Therefore, the job which pays $12 an hour pays more.

7 0
3 years ago
Find the zeros of y = x2 – 6x – 4 by completing the square.
katrin [286]

Answer:

The solutions to the quadratic equations are:

x=\sqrt{13}+3,\:x=-\sqrt{13}+3

Step-by-step explanation:

Given the function

y\:=\:x^2\:-\:6x\:-\:4

substitute y = 0 in the equation to determine the zeros

0\:=\:x^2\:-\:6x\:-\:4

Switch sides

x^2-6x-4=0

Add 4 to both sides

x^2-6x-4+4=0+4

Simplify

x^2-6x=4

Rewrite in the form (x+a)² = b

But, in order to rewrite in the form x²+2ax+a²

Solve for 'a'

2ax = -6x

a = -3

so add a² = (-3)² to both sides

x^2-6x+\left(-3\right)^2=4+\left(-3\right)^2

x^2-6x+\left(-3\right)^2=13

Apply perfect square formula:  (a-b)² = a²-2ab+b²

\left(x-3\right)^2=13

\mathrm{For\:}f^2\left(x\right)=a\mathrm{\:the\:solutions\:are\:}f\left(x\right)=\sqrt{a},\:-\sqrt{a}

solve

x-3=\sqrt{13}

Add 3 to both sides

x-3+3=\sqrt{13}+3

Simplify

x=\sqrt{13}+3

now solving

x-3=-\sqrt{13}

Add 3 to both sides

x-3+3=-\sqrt{13}+3

Simplify

x=-\sqrt{13}+3

Thus, the solutions to the quadratic equations are:

x=\sqrt{13}+3,\:x=-\sqrt{13}+3

4 0
3 years ago
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