2 years ago

What is the formula for time? (something like speed *distance=time??)?

Physics

1 answer:

butalik [34]2 years ago

4 0

It would be: Time = Distance / Speed

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Define newtons first law of motion with examples(class 9 ) plssss itz urgent

Akimi4 [234]

<h3>Newtons first law state that if a body is in motion it will be in motion and if a body is in rest it will tend to be in rest. This phenomena is also called INERTIA. Example: We tend to fall sideways when a car turn suddenly</h3>

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2 years ago

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Isotopes of the same element vary in the number of ____ present in the nucleus A.neutrons

I am Lyosha [343]

A. Neutrons.
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3 years ago

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Classify pH values of 9.1, 1.2, and 5.7 as basic, acidic, or very acidic.

kramer

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3 years ago

For how long should a force of 50,0 N be applied to change the momentum of an object

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2 years ago

What is the energy released in this B- nuclear reaction 2K-> 2Ca0,e? (The atomic mass of 42 K is 41.962403 u and that of 42Ca

Katyanochek1 [597]

<u>Answer:</u> The energy released in the given nuclear reaction is 3.526 MeV.

<u>Explanation:</u>

For the given nuclear reaction:

$_{19}^{42}\textrm{K}\rightarrow _{20}^{42}\textrm{Ca}+_{-1}^{0}\textrm{e}$

We are given:

Mass of $_{19}^{42}\textrm{K}$ = 41.962403 u

Mass of $_{20}^{42}\textrm{Ca}$ = 41.958618 u

To calculate the mass defect, we use the equation:

$\Delta m=\text{Mass of reactants}-\text{Mass of products}$

Putting values in above equation, we get:

$\Delta m=(41.962403-41.958618)=0.003785u$

To calculate the energy released, we use the equation:

$E=\Delta mc^2\\E=(0.003785u)\times c^2$

$E=(0.003785u)\times (931.5MeV)$ (Conversion factor: $1u=931.5MeV/c^2$ )

$E=3.526MeV$

Hence, the energy released in the given nuclear reaction is 3.526 MeV.

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3 years ago