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Vinvika [58]
3 years ago
12

Can prokaryotes have more than one cell

Physics
2 answers:
Westkost [7]3 years ago
5 0
I think the answer is yes, but i might be wrong
GaryK [48]3 years ago
3 0
I think the answer is yes
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The speed of light is 3.00×108m/s. How long does it take for light to travel from Earth to the Moon and back again? Express your
bija089 [108]

Answer:

v = 3×10^8 m/s

s= 384,400 km= 3.84×10^8 m/s

t = ?

v = s/t = 2s/t

t = 2s/v

t = (2×3.84×10^8) ÷ 3×10^8

t = 2.56 seconds

Explanation:

Earth's moon is the brightest object in our

night sky and the closest celestial body. Its

presence and proximity play a huge role in

making life possible here on Earth. The moon's gravitational pull stabilizes Earth's wobble on its axis, leading to a stable climate.

The moon's orbit around Earth is elliptical. At perigee — its closest approach — the moon comes as close as 225,623 miles (363,104 kilometers). At apogee — the farthest away it gets — the moon is 252,088 miles (405,696

km) from Earth. On average, the distance fromEarth to the moon is about 238,855 miles (384,400 km). According to NASA , "That means 30 Earth-sized planets could fit in between Earth and the moon."

7 0
3 years ago
A diver can change his rotational inertia by drawing his arms andlegs close to his body in the tuck position. After he leaves th
NeX [460]

Answer:

3.14946 rad/s

Explanation:

I_i = Intial moment of inertia

I_f = Final moment of inertia

\omega_i = Initial angular velocity

\omega_f = Final angular velocity = \dfrac{2}{1.33}\times 2\pi\ rad/s

\dfrac{I_f}{I_i}=\dfrac{1}{3}

In this system the angular momentum is conserved

L_i=L_f\\\Rightarrow I_i\omega_i=I_f\omega_f\\\Rightarrow \omega_i=\dfrac{I_f\omega_f}{I_i}\\\Rightarrow \omega_i=\dfrac{1\times \dfrac{2}{1.33}\times 2\pi}{3}\\\Rightarrow \omega_i=3.14946\ rad/s

The angular velocity when the diver left the board is 3.14946 rad/s

3 0
2 years ago
The sun is located in
Fiesta28 [93]
Milky Way Galaxy, same one as you.
7 0
2 years ago
Read 2 more answers
A tennis ball is released from a height of 4.0 m above the floor. After its third bounce off the floor, it reaches a height of 1
diamong [38]

Answer:

The percentage of its mechanical energy does the ball lose with each bounce is 23 %

Explanation:

Given data,

The tennis ball is released from the height, h = 4 m

After the third bounce it reaches height, h' = 183 cm

                                                                       = 1.83 m

The total mechanical energy of the ball is equal to its maximum P.E

                                      E = mgh

                                          = 4 mg

At height h', the P.E becomes

                                      E' = mgh'

                                           = 1.83 mg

The percentage of change in energy the ball retains to its original energy,

                                 \Delta E\%=\frac{1.83mg}{4mg}\times100\%

                                  ΔE % = 45 %

The ball retains only the 45% of its original energy after 3 bounces.

Therefore, the energy retains in each bounce is

                                   ∛ (0.45) = 0.77

The ball retains only the 77% of its original energy.

The energy lost to the floor is,

                                E = 100 - 77

                                   = 23 %

Hence, the percentage of its mechanical energy does the ball lose with each bounce is 23 %      

5 0
3 years ago
If 3 and 4 are the magnitudes of victor quantities, when will the magnitude of their sum be 5?
Anika [276]
When they take 2 away 
8 0
3 years ago
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