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3 years ago

5

Children learn to resolve conflicts from surrounding adults.

1 answer:

sergij07 [2.7K]3 years ago

4 0

Answer:

It is true that children learn to resolve conflicts from surrounding adults.

Explanation:

The environment where the children are raised reflects their decision making abilities and conflicts handling power.
Children are the best imitators of the adult around them. From all the activities adults perform around them, they learn that and apply in their life.
So it is always best to take care of our activities that we perform in front of our children.

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Tapping the surface of a pan of water generates 17.5 waves per second. If the wavelength of each wave is 45 cm, what is the spee

ElenaW [278]

Answer:

Speed of the wave is 7.87 m/s.

Explanation:

It is given that, tapping the surface of a pan of water generates 17.5 waves per second.

We know that the number of waves per second is called the frequency of a wave.

So, f = 17.5 Hz

Wavelength of each wave, $\lambda=45\ cm=0.45\ m$

Speed of the wave is given by :

$v=f\lambda$

$v=17.5\times 0.45$

v = 7.87 m/s

So, the speed of the wave is 7.87 m/s. Hence, this is the required solution.

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2 years ago

Peg P is driven by the forked link OA along the path described by r = eu, where r is in meters. When u = p4 rad, the link has an

8_murik_8 [283]

Answer:

The transverse component of acceleration is 26.32 $m/s^2$ where as radial the component of acceleration is 8.77 $m/s^2$

Explanation:

As per the given data

u=π/4 rad

ω=u'=2 rad/s

α=u''=4 rad/s

$r=e^u$

So the transverse component of acceleration are given as

$a_{\theta}=(ru''+2r'u')\\$

Here

$r=e^u\\r=e^{\pi/4}\\r=2.1932 m$

$r'=e^u.u'\\r'=2.1932 \times 2\\r'=4.3864 m$

So

$a_{\theta}=(ru''+2r'u')\\a_{\theta}=(2.1932\times 4+2\times 4.3864 \times 2)\\a_{\theta}=26.32 m/s\\$

The transverse component of acceleration is 26.32 $m/s^2$

The radial component is given as

$a_r=r''-r\theta'^2$

Here

$r''=e^u.u'^2+e^u u''\\r''=2.1932 \times (2)^2+2.1932\times 4\\r''=17.5456 m$

So

$a_r=r''-ru'^2\\a_r=17.5456-2.1932\times (2)^2\\a_r=8.7728 m/s^2$

The radial component of acceleration is 8.77 $m/s^2$

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2 years ago

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BabaBlast [244]

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fgiga [73]

Explanation:

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ladessa [460]

Answer:

SO

Explanation:

SI

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