Answer:
![d=0.165m](https://tex.z-dn.net/?f=d%3D0.165m)
Explanation:
Given
,
,
,![v=2\frac{rev}{s}](https://tex.z-dn.net/?f=v%3D2%5Cfrac%7Brev%7D%7Bs%7D)
The tension of the spring is
![F_{k}=K*x_{1}=m*g](https://tex.z-dn.net/?f=F_%7Bk%7D%3DK%2Ax_%7B1%7D%3Dm%2Ag)
![K=\frac{m*g}{x_{1}}](https://tex.z-dn.net/?f=K%3D%5Cfrac%7Bm%2Ag%7D%7Bx_%7B1%7D%7D)
![K=\frac{0.25kg*9.8m/s^2}{0.05m}=49N/m](https://tex.z-dn.net/?f=K%3D%5Cfrac%7B0.25kg%2A9.8m%2Fs%5E2%7D%7B0.05m%7D%3D49N%2Fm)
The force in the spring is equal to centripetal force so
![F_{c}=\frac{m*v^2}{r}](https://tex.z-dn.net/?f=F_%7Bc%7D%3D%5Cfrac%7Bm%2Av%5E2%7D%7Br%7D)
![v=w*r=2\pi*r](https://tex.z-dn.net/?f=v%3Dw%2Ar%3D2%5Cpi%2Ar)
But Fc is also
Fc=KxΔr
![F_{c}=K*(r-x_{2})](https://tex.z-dn.net/?f=F_%7Bc%7D%3DK%2A%28r-x_%7B2%7D%29)
Replacing
![m*4\pi^2*r=K*(r-x_{2})](https://tex.z-dn.net/?f=m%2A4%5Cpi%5E2%2Ar%3DK%2A%28r-x_%7B2%7D%29)
![0.25kg*4\pi^2*r=49*(r-0.04m)](https://tex.z-dn.net/?f=0.25kg%2A4%5Cpi%5E2%2Ar%3D49%2A%28r-0.04m%29)
![r=0.205m](https://tex.z-dn.net/?f=r%3D0.205m)
total distance is
![d=0.205-0.04=0.165m](https://tex.z-dn.net/?f=d%3D0.205-0.04%3D0.165m)
Explanation:
For example, when a drum is struck, the flexible skin (sometimes called a membrane) of the drum vibrates. The compression and expansion of the air on either side of the vibrating membrane produces differences in air pressure. The pressure differences generate a sound wave that propagates outward from the drum surface.
A scientist would write that number as 1.49 x 10⁸ kilometers .
(Or, if the scientist is in France or the UK, he might write it as 1.49 x 10⁸ kilometres .)
Answer:
40 N/m
Explanation:
F = -kx (This is the Hooke's Law equation)
F is the force the spring exerts = 8 N
-k = spring constant
x = displacement (The distance stretched past it's natural length) = 20cm
x needs to be in meters, and 20 cm is = to 0.2 meters
Finally:
8N = -k (0.2m)
-k = 8N / 0.2 m
k = -40 N/m
Answer:
True
Explanation:
Magnitude is the "value" the greater the value the greater the force is and vice versa