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Vesnalui [34]
2 years ago
15

In an experiment similar to the one you performed in Week 3, an experimenter measures the count rate of a radioactive element 10

0 times, calculates the mean and standard deviation of the data, and organizes the data into four bins:
Interval Number of Occurrences
n < n 15
< n < n 50 - 15
n < n < + 38
n > n + 12
The experimenter expects a Gaussian distribution. (For simplicity, assume 68 % of the counts fall within one standard deviation of the mean rather than the more exact value of 68.27 \%.) What is x?
Physics
1 answer:
suter [353]2 years ago
3 0

Answer:

The answer is "1.5625".

Explanation:

Please find the complete question with its solution file in the attachment.

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A proton with an initial speed of 600,000 m/s is brought to rest by an electric field. Part A Part complete Did the proton move
rodikova [14]

Answer: Part A the right sentence is: Because the proton is a positive charge and it slows down as it travels, it must be moving from a region of lower potential to a region of higher potential

Part B.  aproximatelly 98 times ΔV  V

Part C. the initial kinetic energy of the proton is 1.87 10^3 eV

Explanation: Part A. The field stops the proton so the lines of electric fild must be directed in opposite direction of its movement. This means that the proton moves to a higher potential. Part B The kinetic energy of the  is transformed  in electric potenctial for the proton.

Part C. Energy in J divide the charge of electron gives the energy  in eV.

7 0
2 years ago
Please help! Will give a lot of points
krek1111 [17]
Answer:

Chemical and Biological weathering.

Explanation:

Processes that break down and weaken earth minerals are known as weathering. Over time, this can lead to erosion, in which huge sections of rock and stone are carried away, changing landscapes. Physical weathering alters the material structure of rocks, while chemical weathering alters their chemical structure.
3 0
2 years ago
A stone is launched from the ground, at a 70° angle, with an initial velocity of 120 m/s.
zavuch27 [327]
<span>A) x = 41t
    The classic equation for distance is velocity multiplied by time. And unfortunately, all of your available options have the form of that equation. In fact, the only difference between any of the equations is what looks to be velocity. And in order to solve the problem initially, you need to divide the velocity vector into a vertical velocity vector and a horizontal velocity vector. And the horizontal velocity vector is simply the cosine of the angle multiplied by the total velocity. So H = 120*cos(70) = 120*0.34202 = 41.04242 So the horizontal velocity is about 41 m/s. Looking at the available options, only "A" even comes close.</span>
3 0
3 years ago
Read 2 more answers
A 4.33 kg cat has 41.7 J of KE How fast is the cat moving?
balandron [24]

Answer:

The answer to your question is:

Explanation:

Data

mass = 4.33 kg

E = 41.7 J

v = ?

Formula

Ke = (1/2)mv²

Clear v from the equation

v = √2ke/m

Substitution

v = √2(41.7)/4.33

v = 19.26 m/s          Result

7 0
3 years ago
A charge of -3.02 μC is fixed in place. From a horizontal distance of 0.0377 m, a particle of mass 9.43 x 10^-3 kg and charge -9
Andreyy89

Answer:

d = 0.0306 m

Explanation:

Here we know that for the given system of charge we have no loss of energy as there is no friction force on it

So we will have

U + K = constant

\frac{kq_1q_2}{r_1} + \frac{1}{2}mv_1^2 = \frac{kq_1q_2}{r_2} + \frac{1}{2}mv_2^2

now we know when particle will reach the closest distance then due to electrostatic repulsion the speed will become zero.

So we have

\frac{(9 \times 10^9)(3.02 \mu C)(9.78 \mu C)}{0.0377} + \frac{1}{2}(9.43 \times 10^{-3})(80.4)^2 = \frac{(9 \times 10^9)(3.02 \mu C)(9.78 \mu C)}{r} + 0

7.05 + 30.5 = \frac{0.266}{r}

r = 7.08 \times 10^{-3} m

so distance moved by the particle is given as

d = r_1 - r_2

d = 0.0377 - 0.00708

d = 0.0306 m

6 0
3 years ago
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