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natima [27]
2 years ago
10

Determine the resultant moment of the forces acting about the x, y, and z axes. Suppose that f1 = 200 n, f2 = 60 n, f3 = 115 n,

and f4 = 300 n. (figure 1).
Physics
1 answer:
SpyIntel [72]2 years ago
5 0

Based on the forces acting on the axes, the resultant moments will be (345, 400, 600 N·m)

<h3>What would be resultant moment about x-axis?</h3>

= F₃ x 3

= -115 x 3

= -345 N·m

<h3>What would be resultant moment about y-axis?</h3>

= F₁ x 2

= -200 x 2

= -400 N·m

<h3>What would be the resultant moment about z-axis?</h3>

= F₄ x 2

= -300 x 2

= - 600 N·m

In conclusion, the resultant moment about x, y, and z axes is (345, 400, 600 N·m)

Find out more on resultant moments at brainly.com/question/6278006.

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Find the speed of a rock being thrown 20.5 meters (m) to the left in 4.0s.
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5.125

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8 0
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Read 2 more answers
You have two points in a soil. Point A is at 75 cm; point B is at 25 cm above the reference. The capillary potential energy at p
user100 [1]

Answer:

The potential energy at point A is 17.1675 J

Explanation:

The capillary potential is the work expended to bring up a unit mass of liquid to a point in a capillary region from a level liquid surface. It is the capillary potential that facilitates the movement of moisture within soil capillaries

In meteorology it is used to describe the level of saturated soil above the water table

Potential energy is the energy inherent in a body by virtue of its position, therefore the potentials of both point A and B are

Point A, elevation = 75 cm capillary potential = -100 cm

Point B, elevation = 25 cm capillary potential = -200 cm

The total potential energy at point A is

Elevation above reference - capillary potential =75-(-100) = 175 cm

which gives per unit mass

PE = m × g × h = 1 kg × 9.81 m/s ² × 1.75 m = 17.1675 kg·m²/s² = 17.1675 J

8 0
3 years ago
if the angular momentum of a rigid body is changing, does that mean that there must be a net torque acting on the body?
masha68 [24]

The attribute of any rotating object determined by the product of the moment of inertia and the angular velocity is known as angular momentum.

<h3>What is Angular Momentum?</h3>
  • Without a kickstand, attempting to balance while getting on a bicycle will definitely result in you falling off. However, these wheels gain angular momentum once you begin pedaling. They're going to be resistant to change, which will make balance simpler.
  • The definition of angular momentum is:  any rotating object's characteristic determined by moment of inertia times angular velocity.
  • It is a characteristic of rotating bodies determined by the sum of their moment of inertia and angular velocity. Since it is a vector quantity, the direction must also be taken into account in addition to the magnitude.
  • Angular Momentum Examples : We encounter this property frequently, whether knowingly or unknowingly.
  • The following provides some examples : Ice-skater
  • In order to begin a spin, an ice skater starts with her hands and legs spread widely from the center of her body. She moves her hands and leg closer to her body when she needs to spin with more angular velocity, though.
  • As a result, she conserves angular momentum and spins faster.

To Learn more About angular momentum refer to :

brainly.com/question/26889176

#SPJ4

6 0
1 year ago
Two equal point charges QQQ are separated by a distance ddd. One of the charges is released and moves away from the other due on
lys-0071 [83]

Answer:

The kinetic energy K of the moving charge is K = 2kQ²/3d = 2Q²/(4πε)3d = Q²/6πεd

Explanation:

The potential energy due to two charges q₁ and q₂ at a distance d from each other is given by U = kq₁q₂/r.

Now, for the two charges q₁ = q₂ = Q separated by a distance d, the initial potential energy is U₁ = kQ²/d. The initial kinetic energy of the system K₁ = 0 since there is no motion of the charges initially. When the moving charge is at a distance of r = 3d, the potential energy of the system is U₂ = kQ²/3d and the kinetic energy is K₂.

From the law of conservation of energy, U₁ + K₁ = U₂ + K₂

So, kQ²/d + 0 = kQ²/3d + K

K₂ = kQ²/d - kQ²/3d = 2kQ²/3d

So, the kinetic energy K₂ of the moving charge is K₂ = 2kQ²/3d = 2Q²/(4πε)3d = Q²/6πεd

4 0
3 years ago
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