Answer:
The frequency of the tuning is 1.065 kHz
Explanation:
Given that,
Length of tube = 40 cm
We need to calculate the difference between each of the lengths
Using formula for length
For an open-open tube,
We need to calculate the fundamental wavelength
Using formula of wavelength
Put the value into the formula
We need to calculate the frequency of the tuning
Using formula of frequency
Put the value into the formula
Hence, The frequency of the tuning is 1.065 kHz
Answer:
d = 0.076 mm
Explanation:
Given data
diffraction pattern d1 = 0.19 mm = 0.019 cm
separated s(1) = 1.8 cm
separated s(2) = 4.5 cm
to find out
d2 for an unknown
solution
we know here that spacing in between the diffraction fringe is always inversely proportional to diffraction grating so
we will apply here formula for unknown d that is
d1 (s1 / L) = d2 (s2 /L)
d2 = d1 × s(1) / s(2)
put here all thes evalue we get d2
d2 = d1 × s(1) / s(2)
d2 = 0.019 × 1.8 / 4.5
d2 = 0.0076 cm
d2 = 0.076 mm
The resistance is 4 times the resistance of the first wire. the formula is R = p*l/A with p being resistivity, l length and A area. So if you double length and half area, which botv result in more resistance, you get p*2/0.5 or 4 (p can be abandoned because it is the same. We take standard length and area as 1)
The wall will push back, in exactly the opposite direction, and with
exactly the same size force.
That's why the net force on the palm of your hand is zero, and that
in turn is the reason that your hand doesn't accelerate.
If you keep increasing the strength of your push, then eventually you
exceed the force that the wall is capable of delivering. Then the wall
crumbles and falls, your hand accelerates in the direction you're pushing,
and the crowd goes wild !
