We have: v i (initial velocity) = 6 m/sv = 1.1 m/sa = - 9.8 m/s²v = v i + a · t1.1 m/s = 6 m/s - 9.8 m/s² t9.8 t = 6 - 1.19.8 t = 4.9t = 4.9 : 9.8t = 0.5 sThen the replacement:x = xi + vi · t + a t² / 2( xi = 0 )x = 6 · 0.5 - 9.8 · 0.25 / 2x = 3 - 1.225Answer:
x = 1.775 m
Answer:
W = 600 J
Explanation:
We have,
According to attached figure,
Height of the inclined plane is 60 m
Force acting on the block is 10 N
It is required to find the work must be done against gravity to move it to the top of the incline. The work done is given by :
W = mgh
or

So, the work done against the gravity is 600 J.
Answer:
(a) 
(b) 
Explanation:
(a) Since a constant external force is applied to the body, it is under an uniformly accelerated motion. Using the following kinematic equation, we calculate the final velocity of the mass if it is initially at rest(
):

According to Newton's second law:

Replacing (2) in (1):

(b) In this case we have
. So, we use the final velocity equation:
