Here, we are required to find the first term of an arithmetic progression which has a second term of 96 and a fourth term of 54.
- The first term of the progression which has a <em>second term</em> of 96 and a <em>fourth term</em> of 54 is; a = 117.
<em>In Arithmetic progression, the N(th) term of the progression is given by the formular;</em>
T(n) = a + (n-1)d
where;
Therefore, from the question above;
- T(2nd) = a + d = 96..............eqn(1)
- and T(4th) = a + 3d = 54..........eqn(2)
By solving the system of equations simultaneously;
we subtract eqn. 2 from 1, then we have;
<em>-2d = 42</em>
Therefore, d = -21.
However, the question requests that we find the first term of the progression; From eqn. (1);
a + d = 96
Therefore,
Ultimately, the first term of the progression is therefore; a = 117
Read more:
brainly.com/question/18828482
Y coordinate (0,275) x coordinate (175,0)
Answer:let 't' represent the cost of a taco and 'm' represent the cost of a glass of milk
Step-by-step explanation:2.10 = t + m
5.15 = 2t + 3m
128*.69=88.32-8.83
128+8.83=136.83
Answer choice B is the answer.
