Answer:
Only A is not Pythagorean Identity.
Step-by-step explanation:
Let us draw a unit circle as shown in the attached figure.
In the given figure, let us apply Pythagorean theorem, which is given by
![x^2+y^2=z^2\\\\x=\sin\theta,y=\cos\theta,z=1\\\\\sin^2\theta+\cos^2\theta=1^2\\\\\sin^2\theta+\cos^2\theta=1........(C)](https://tex.z-dn.net/?f=x%5E2%2By%5E2%3Dz%5E2%5C%5C%5C%5Cx%3D%5Csin%5Ctheta%2Cy%3D%5Ccos%5Ctheta%2Cz%3D1%5C%5C%5C%5C%5Csin%5E2%5Ctheta%2B%5Ccos%5E2%5Ctheta%3D1%5E2%5C%5C%5C%5C%5Csin%5E2%5Ctheta%2B%5Ccos%5E2%5Ctheta%3D1........%28C%29)
Divide both sides by ![\sin^2\theta](https://tex.z-dn.net/?f=%5Csin%5E2%5Ctheta)
![\frac{\sin^2\theta}{\sin^2\theta}+\frac{\cos^2\theta}{\sin^2\theta}=\frac{1}{\sin^2\theta}\\\\1+\cot^2\theta=\csc^2\theta.......(B)](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csin%5E2%5Ctheta%7D%7B%5Csin%5E2%5Ctheta%7D%2B%5Cfrac%7B%5Ccos%5E2%5Ctheta%7D%7B%5Csin%5E2%5Ctheta%7D%3D%5Cfrac%7B1%7D%7B%5Csin%5E2%5Ctheta%7D%5C%5C%5C%5C1%2B%5Ccot%5E2%5Ctheta%3D%5Ccsc%5E2%5Ctheta.......%28B%29)
Divide both side of identity C by ![\sin^2\theta](https://tex.z-dn.net/?f=%5Csin%5E2%5Ctheta)
![\frac{\sin^2\theta}{\cos^2\theta}+\frac{\cos^2\theta}{\cos^2\theta}=\frac{1}{\cos^2\theta}\\\\\tan^2\theta+1=\sec^2\theta.......(D)](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csin%5E2%5Ctheta%7D%7B%5Ccos%5E2%5Ctheta%7D%2B%5Cfrac%7B%5Ccos%5E2%5Ctheta%7D%7B%5Ccos%5E2%5Ctheta%7D%3D%5Cfrac%7B1%7D%7B%5Ccos%5E2%5Ctheta%7D%5C%5C%5C%5C%5Ctan%5E2%5Ctheta%2B1%3D%5Csec%5E2%5Ctheta.......%28D%29)
Therefore, only A is not Pythagorean Identity.
Answer:
I believe the answer would be using the form of y= mx+b, b is y intercept and slope is m. It would end up looking like y= 2/3x+1
Step-by-step explanation:
I think this is how a linear equation looks like but I'm a little rusty. If you have notes it probably says what I already stated. Good luck! :)
The answer would be 28 pages because 280 divided by 10% or .10 is 28
Answer:
a. (15, 15)
Step-by-step explanation:
We start with those two equations:
1) a - 1.2b = -3
2) 0.2b + 0.6a = 12
We'll begin by modifying equation #1 to isolate a:
a = -3 + 1.2b
Then we'll use this value for a in the second equation:
0.2b + 0.6 (-3 + 1.2b) = 12
0.2b - 1.8 + 0.72b = 12
0.92b = 13.8
b = 15
Then we'll place that value of b in the first equation to find a:
a - 1.2 (15) = -3
a - 18 = -3
a = 15
Note that the domain of a function whose graph is shown is the projection of the graph into the x-axis.
So, if we projected (or mapped) the graph to the x-axis, the whole negative x-axis, + 0, would be 'colored in blue'. So, the domain is (-∞, 0].
Similarly, the range is found by mapping into the y-axis. So, we see that the range of the function is (-∞, 0], as the whole negative y-axis, +0, would be colored in blue.
The only right answer is: the domain and the range of the function are the same.