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viva [34]
3 years ago
13

When running a marathon what kind of energy transformation takes place

Physics
1 answer:
xz_007 [3.2K]3 years ago
5 0
Thermal energy is transforming, i think.
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Suppose that a planet were discovered between the sun and Mercury, with a circular orbit of radius equal to 2/3 of the average o
Musya8 [376]

Explanation:

It is given that,

A planet were discovered between the sun and Mercury, with a circular orbit of radius equal to 2/3 of the average orbit radius of Mercury.

Mass of the Sun, M=1.99\times 10^{30}\ kg

Radius of Mercury's orbit, r=5.79\times 10^{10}\ m

Radius of discovered planet, R=\dfrac{2}{3}r

R=\dfrac{2}{3}\times 5.79\times 10^{10}\ m=3.86\times 10^{10}\ m

Let T is the orbital period of such a planet. Using Kepler's third law of planetary motion as :

T^2\propto R^3

T^2=\dfrac{4\pi^2R^3}{GM}

T^2=\dfrac{4\pi^2\times (3.86\times 10^{10})^3}{6.67\times 10^{-11}\times 1.99\times 10^{30}}

T=\sqrt{1.71\times 10^{13}}

T = 4135214.625 s

or

T = 47.86 days

So, the orbital period of such a planet is 47.86 days. Hence, this is the required solution.

6 0
3 years ago
Supposing d(t) is known to have value D,
creativ13 [48]

Answer:

  • The procedure is: solve the quadratic equation for t.

Explanation:

This question assumes uniformly accelerated motion, for which the distance d a particle travels in time t is given by the general equation:

  • d(t)=d_0+v_0t+at^2/2

That is a quadratic equation, where the independent variable is the time t.

Thus, the procedure that will find the time t at which the distance value is known to be D is to solve the quadratic equation for t.

To solve it you start by changing the equation to the general form of the quadratic equations, rearranging the terms:

  • (a/2)t^2+v_0t+(d_0-D)=0

Some times that equation may be solved by factoring, and always it can be solved by using the quadratic formula:

  • t=\frac{-b+/-\sqrt{b^2-4ac} }{2a}

Where:

a=-a/2\\ \\ b=v_0\\ \\ c=d_0-D

That may have two solutions. Some times one of the solution makes no physical sense (for example time cannot be negative) but others the two solutions are valid.

5 0
3 years ago
A physical change can be distinguished from a chemical change because during a physical change- A. the properties of the substan
joja [24]

Answer:

a

Explanation:

yw

3 0
2 years ago
. A non-uniform positive line charge of length 2 m is put along the x-axis as shown in the figure, where x​0​=1.5 m. The linear
PilotLPTM [1.2K]

Answer:

E = 7.2*10^{10}N/C

Explanation:

The differential electric field dE due to differential charge dQ at distance x from the origin is

dE = k\dfrac{dQ}{x^2}

but since dQ = \lambda dx = 4x^2dx we have

dE = k\dfrac{4x^2dx}{x^2}

dE = 4k\: dx

integrating this from x_0 to x_0+L we get

$E = \int^{x_0+L}_{x_0} {4k} \, dx $

E = 4k[(x_0+L)-x_0]

E =4kL

putting in k = 9*10^9Nm^2/C^2 and L =2m we get

\boxed{E = 7.2*10^{10}N/C.}

5 0
3 years ago
A push or pull is called a force. Unbalanced forces can cause objects to move in many ways but not to move faster. B) move slowe
Allushta [10]

Answer:

but not to

D). float in the air

6 0
3 years ago
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