Answer:
The repulsive force is 
.
Step-by-step explanation:
Consider the provided information.
The coulomb's law to calculate the repulsive force: 
Where the value of k is 9.00×10⁹ Nm²/C²
Substitute the respective values in the above formula.
![F=\frac{9\times10^9\frac{N\cdot m^2}{c^2} \times(-24\times10^{-9}C)^2}{[(13 cm)(\frac{1m}{100cm} )]^2}](https://tex.z-dn.net/?f=F%3D%5Cfrac%7B9%5Ctimes10%5E9%5Cfrac%7BN%5Ccdot%20m%5E2%7D%7Bc%5E2%7D%20%5Ctimes%28-24%5Ctimes10%5E%7B-9%7DC%29%5E2%7D%7B%5B%2813%20cm%29%28%5Cfrac%7B1m%7D%7B100cm%7D%20%29%5D%5E2%7D)
Hence, the repulsive force is .
The best description to simplify 34/3 would be 11.33 on going
Answer:
(A) s + g + ( g + 25) = 425
Step-by-step explanation:
When x = 1
5(1) = -y + 6
5 = -y + 6
y = 6 - 5 = 1
When x = 2
5(2) = -y + 6
10 = -y + 6
y = 6 - 10 = -4
When x = 3
5(3) = -y + 6
15 = -y + 6
y = 6 - 15 = -9
B. 12 and 25 is the answer.....
Hope this helps!
