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baherus [9]
4 years ago
12

Consider a political discussion group consisting of 9 ​Democrats, 7 ​Republicans, and 3 Independents. Suppose that two group mem

bers are randomly​ selected, in​ succession, to attend a political convention. Find the probability of selecting no Democrats
Mathematics
1 answer:
Scorpion4ik [409]4 years ago
7 0
Well, first you would add up how many objects you have to select from

9 democrats + 7 Republicans + 3 Independents = 19 total people
so then you would put how many people you can have over that number
so since we don't want any Democrats it would be 10/19 (.52)
and that tells you the chances of not picking one the first time

then, since that person cannot be selected again, we remove them from the pool, making it only 18 people to pick from and 9 people you want picked so once again you put 9/18 (.50), then you take those, (in decimal form) and multiply them (.26) then convert it to a fraction by moving the decimal to the right two and have 26% chance of no Democrats <span />
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Please help! I attached the question below.
kompoz [17]

Answer:

\frac{2(c+2)}{c(c-2)}

Step-by-step explanation:

\frac{c^{2}-4 }{6c^{4}+15c^{3}}=\frac{(c-2)(c+2)}{c(6c^{3}+15c^{2}) }

Identity used:

a^{2}-b^{2}=(a-b)(a+b)

\frac{c^{2}-4c+4}{12c^{3}+30c^{2}}=\frac{(c-2)^{2}}{2(6c^{3}+15c^{2}) }

Now let us divide the modified expressions:

\frac{(c-2)(c+2)}{c(6c^{3}+15c^{2})} ÷ \frac{(c-2)^2}{2(6c^{3}+15c^{2}) }

we get:

\frac{2(c+2)}{c(c-2)}

5 0
4 years ago
Please help me (9-7×3+4)^2
kherson [118]
(9 - 7 × 3 + 4)²
(9 - 21 + 4)²
(9 - 17)²
(-12)²
144
5 0
4 years ago
Kristen and Mitchell were given the same math assignment. Kristen completes 0.8 of her work in class. Mitchell completes 0.75 of
monitta
Mitchell because if you add a zero at the end of the .8 it would be 0.80 and 0.75 is smaller than 0.80 so Mitchell has more work to do at home
5 0
4 years ago
A hair salon charges a fixed rate of $25.00 for a haircut and an additional $15 for any other services. Write a function to mode
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25+15•3= 70 dollars she spent on the hair salon..... dang lotsa money
3 0
4 years ago
Read 2 more answers
Explain why 2+x and x+3 are equivalent
wlad13 [49]

Check whether the two expressions 2x+3y2x+3y and 2y+3x2y+3x equivalent.

The first expression is the sum of 2x2x 's and 3y3y 's whereas the second one is the sum of 3x3x 's and 2y2y 's.

Let us evaluate the expressions for some values of xx and yy . Take x=0x=0 and y=1y=1 .

2(0)+3(1)=0+3=32(1)+3(0)=2+0=22(0)+3(1)=0+3=32(1)+3(0)=2+0=2

So, there is at least one pair of values of the variables for which the two expressions are not the same.

5 0
3 years ago
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