The vertices of abc given the transition rule (x,y)-->(x,y-3) are (-6, -10), (-3, -13) and (-5, -1)
<h3>How to determine the new vertices?</h3>
The vertices are given as:
a (-6,-7)
b(-3,-10)
c(-5,2)
The transition rule is given as
(x,y)-->(x,y-3)
So, we have
a' = (-6, -7 - 3)
a' = (-6, -10)
b' = (-3, -10 - 3)
b' = (-3, -13)
c' = (-5, 2 - 3)
c' = (-5, -1)
Hence, the vertices of abc given the transition rule (x,y)-->(x,y-3) are (-6, -10), (-3, -13) and (-5, -1)
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Answer:
8 ft
Step-by-step explanation:
Use pythagorean theorem.
. Put 10 and 6 into the equation as b and c.


Therefore, the answer is 8ft.
A diagram is attached. Sorry it's kinda messy.
Both numbers are zero (0,0)
It is 1/4 but I don’t know why
Th total possible outcomes are 6^3 = 216
The possible ways of getting 15 are
555
456
465
546
564
645
654
366
663
636
= 10
so P(sum of 15) = 10/216 = 5/108