Answer:
23 days.
Step-by-step explanation:
Let the original amount of radioactive material be 100.
We have been given that the half life of a radioactive material is 8 days. It is safe to feed the hay to cows when 14% of the radioactive isotope remains. We are asked to find the number of days, the farmers need to wait to use the radioactive contaminated hay.
We will use half-life formula to solve our given problem.
, where,
A = Amount left after t time,
a = Initial amount,
h = Half-life.
14% of 100 would be 14.



Now, we will take natural log of both sides.

Using natural log property
, we will get:









Therefore, the farmers need to wait for 23 days.
Answer:
The answer to 4.7 times 2.65 equals 12.455
First, you want to distribute the 6 and the -3. This turns you equation into 18n+6+3-6n=n+2. Next, put all the n's on one side and numbers on the other. 18n-6n-n=2-6-3. Then, combine. 11n=-7 -> n=-7/11. Hope this helps!
Answer:
2
Step-by-step explanation: