Answer: We can find out the missing statement with help of below explanation.
Step-by-step explanation:
We have a rectangle ABCD with diagonals AC and BD ( shown in given figure.)
We have to prove: Diagonals AC and BD bisect each other.
In triangles, AED and BEC.
( By alternative angle theorem)
( Because ABCD is a rectangle)
( By alternative angle theorem)
By ASA postulate,
By CPCTC, and
⇒ BE= ED and CE=EA
By the definition of bisector, AC and BD bisect each other.
Answer:
9.85
Step-by-step explanation:
I hate these, LOL
We're going to draw a triangle on the graph paper to solve this. (in theory)
The top point is at 2 on the x axis, and the bottom is at 6. That's a difference of 4. Draw a line from the top dot over 4 spaces, so a line dropped from there could go straight to the bottom dot. We'll call this line/side of the triangle a, and a = 4.
Then we drop the line from there (6, 4) down to the second dot at (6, -5). That line is 9 places long. We'll call this line/side of the triangle b, and b = 9.
(This is so much easier to draw than type, I'll attach a picture).
Then we connect the two dots diagonally to form line/side c of our triangle. This is the length we don't know.
The pythagorean theorem says a^2 + b^2 = c^2
So a = 4, b = 9, c is unknown for our triangle
(4)(4) + (9)(9) = c^2
16 + 81 = 97
The square root of 97 = 9.8488, so if they have you round, I would say 9.85
Sorry if this just confused you more.
