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goblinko [34]
2 years ago
10

Can anyone help with this, it’s my worst subject.

Mathematics
2 answers:
7nadin3 [17]2 years ago
7 0
Yes^ they are congregant because they have the same measurements
Zina [86]2 years ago
5 0

Answer:

Yes

Step-by-step explanation:

They are congruent because they gave the same dimensions.

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Please help!! This is for a test!!
masya89 [10]
Cos=(adjacent/hypotenuse)
So the answer will be cos(16/20) or cos(4/5) both will give u the same answer
I hope it helps
6 0
3 years ago
Simplify the following expression.
Aleksandr [31]
The correct answer is option A
8 0
2 years ago
Read 2 more answers
A frame designer is making a triangular frame. She has two sides of length 18 inches and 27 inches. What are the possible length
zlopas [31]

Answer:

Therefore, the possible lengths (in whole inches) for the third side is

9 inches < x < 45 inches

Step-by-step explanation:

For the above question, we have a rule, the sum of the length of any two sides of the triangle must be greater than the length of the third side.

Hence:

She has two sides of length 18 inches and 27 inches

Let the third side = x

Hence:

a) 18 + 27 > x

45 > x

b) 18 + x > 27

x > 27 - 18

x > 9

Therefore, the possible lengths (in whole inches) for the third side is

9 inches < x < 45 inches

5 0
3 years ago
50,000 contestants participate in an on-line game. The game randomly eliminates 20% of the contestants each day. Determine the n
irga5000 [103]

Answer:10,486 contestants

Step-by-step explanation:

First day:

Total number of contestants at the beginning = 50,000

After first day, 20% 0f 50,000 are removed.

That is, (20/100)×50,000 = 10,000

Contestants remaining after first day = 50,000-10,000 = 40,000

Second day:

Contestants= 40,000

20% removed

That is (20/100)×40000=8000

Balance =40000-8000=32,000

Third day:

Contestants= 32000

20% removed

That is (20/100)×32000=6400

Balance =32000-6400=25,600

Fouth day:

Contestants= 25,600

20% removed

That is (20/100)×25,600=5,120

Balance =25,600-5,120=20,480

Fifth day:

Contestants= 20,480

20% removed

That is (20/100)×20,480=4096

Balance =20,480-4096=16,384

Sixth day:

Contestants= 16,384

20% removed

That is (20/100)×16,384=3276.8

Balance =16,384-3276.8=13,107.2

Seventh day:

Contestants= 13,107.2

20% removed

That is (20/100)×13,107.2=2621.44

Balance =13107.2-2621.44=10485.76

Therefore, number of contestants remaining after one week equals 10,486.

6 0
3 years ago
Help! This is due tomorrow!
Ira Lisetskai [31]
So you're combining equations correct?
6 0
3 years ago
Read 2 more answers
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