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3 years ago

Can anyone help with this, it’s my worst subject.

Mathematics

2 answers:

7nadin3 [17]3 years ago

7 0

Yes^ they are congregant because they have the same measurements

Zina [86]3 years ago

5 0

Answer:

Yes

Step-by-step explanation:

They are congruent because they gave the same dimensions.

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What is the mode of the data set?

saw5 [17]

Answer: 92 which is choice D

Look at the right side of values for the digit that comes up the most. In this case, it would be '2' in the second row. It shows up 3 times. Those leafs pair up with the stem of 9 to form the full value 92. So we have 92 show up three times which is the most frequent value.

The data set would expand out to

85, 88

92, 92, 92, 98

105, 106, 106, 109

113

126, 127

5 0

3 years ago

100 point reward with certified answer. 4 basic algebra questions, must show work. If the answers are wrong your response will b

ipn [44]

Y=kx
12=-4k
k = -3

so when y = 15
y = kx
15 = -3x
x = -5

----------------

$50 / 0.04 = $1250 (4% interest)

so
1250 * 0.06 = $75

answer
interest $75 at 6%

-----------------------------

y = kx
1/4 = 4k
k = 1/16

when x = 5
y = kx
y = 1/16(5)
y = 5/16

-----------
y = kx
-5 = 4k
k = -5/4

direct equation
y = -5/4x

6 0

3 years ago

A tank contains 30 lb of salt dissolved in 300 gallons of water. a brine solution is pumped into the tank at a rate of 3 gal/min

sesenic [268]

$A'(t)=(\text{flow rate in})(\text{inflow concentration})-(\text{flow rate out})(\text{outflow concentration})$
$\implies A'(t)=\dfrac{3\text{ gal}}{1\text{ min}}\cdot\left(2+\sin\dfrac t4\right)\dfrac{\text{lb}}{\text{gal}}-\dfrac{3\text{ gal}}{1\text{ min}}\cdot\dfrac{A(t)\text{ lb}}{300+(3-3)t\text{ gal}}$
$A'(t)+\dfrac1{100}A(t)=6+3\sin\dfrac t4$

We're given that $A(0)=30$ . Multiply both sides by the integrating factor $e^{t/100}$ , then

$e^{t/100}A'(t)+\dfrac1{100}e^{t/100}A(t)=6e^{t/100}+3e^{t/100}\sin\dfrac t4$
$\left(e^{t/100}A(t)\right)'=6e^{t/100}+3e^{t/100}\sin\dfrac t4$
$e^{t/100}A(t)=600e^{t/100}-\dfrac{150}{313}e^{t/100}\left(25\cos\dfrac t4-\sin\dfrac t4\right)+C$
$A(t)=600-\dfrac{150}{313}\left(25\cos\dfrac t4-\sin\dfrac t4\right)+Ce^{-t/100}$

Given that $A(0)=30$ , we have

$30=600-\dfrac{150}{313}\cdot25+C\implies C=-\dfrac{174660}{313}\approx-558.02$

so the amount of salt in the tank at time $t$ is

$A(t)\approx600-\dfrac{150}{313}\left(25\cos\dfrac t4-\sin\dfrac t4\right)-558.02e^{-t/100}$

3 0

3 years ago

When three pipes fill a pool, they can finish in 12 hours. Two of the pipes can finish in 18 hours if they are working together.

ladessa [460]

3 pipes take 12 hours
⇒ In 1 hour, the 3 pipes can fill 1/12 of the pool

2 of the pipes take 18 hours
⇒ in 1 hour, the 2 pipes can fill 1/18 of the pool

In 1 hour, the third pipe alone can fill :

$\dfrac{1}{12} - \dfrac{1}{18} = \dfrac{3}{36} - \dfrac{2}{36} = \dfrac{1}{36} \text { of the pool}$

Time needed :

$1 \div \dfrac{1}{36} = 1 \times 36 = 36 \text { hours}$

----------------------------------------------------------------------------------------
Answer: It will take 36 hours for the third pipe to fill the pool.
----------------------------------------------------------------------------------------

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3 years ago

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Who has insta grammm I need help with my music assignments I’ll pay u 30$

KIM [24]

Answer:

i have it and and wht the assiment about et me see it

Step-by-step explanation:

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3 years ago

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